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anonymous
 one year ago
Britney throws an object into the air with an initial vertical velocity of 27 ft/s from a platform that is 10 ft above the ground. About how long will it take the object to hit the ground?
A. 1 s
b. 2 s
c. 3 s
d. 4 s
anonymous
 one year ago
Britney throws an object into the air with an initial vertical velocity of 27 ft/s from a platform that is 10 ft above the ground. About how long will it take the object to hit the ground? A. 1 s b. 2 s c. 3 s d. 4 s

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mathmate
 one year ago
Best ResponseYou've already chosen the best response.0@yayah2001 Are you on energy conservation or kinematics? Both will solve the problem, but it's better to work with the one you're studying.

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0So you're on calculus?

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0Do you have the kinematics equation given to you? like: x(t)=vt+(1/2)at^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have h(t)=4.9t^2 + VoT +Ho

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0x(t)=10 v=+27 a=32.2 Solve for t.

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0That is assuming the ball was thrown vertically \(upwards\)

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0and reject the negative root from the quadratic equation.

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0That's the same equation, but the number 4.9 should read 16 or 16.1, because you are working with feet, not metres.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay, I understand now.

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0Take your time and post the answer to check if you wish. Please give me the answer to 2 places of decimals, even though you have to round it to an integer later on. Remember to reject the negative root.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have to change it to a different question because I got a 70%

mathmate
 one year ago
Best ResponseYou've already chosen the best response.0ok, anyway, the principle is the same.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I really just need the answer. I've tried really hard to get the equation right (I spent 10 minutes on just the one question), so could you possibly go easy on me?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0with the new question, of course.
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