MTALHAHASSAN2
  • MTALHAHASSAN2
Need help!! Solve a) log base x 625 =4
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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geerky42
  • geerky42
Hint: \(\log_x625 = \dfrac{\log 625}{\log x}\)
geerky42
  • geerky42
Can you handle it now?
Loser66
  • Loser66
We have equivalent formulas. Those are \(log_a b= c\iff a^c =b\)

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More answers

Loser66
  • Loser66
like \(log_2 8 = 3 \iff 2^3 =8\) Same as your problem, you can convert from log to exponent and solve for x
MTALHAHASSAN2
  • MTALHAHASSAN2
thnx a lot both of you
MTALHAHASSAN2
  • MTALHAHASSAN2
wait but how can we do this one
MTALHAHASSAN2
  • MTALHAHASSAN2
|dw:1432954382672:dw|
MTALHAHASSAN2
  • MTALHAHASSAN2
|dw:1432954474494:dw|
MTALHAHASSAN2
  • MTALHAHASSAN2
can someone plz help me with it
MTALHAHASSAN2
  • MTALHAHASSAN2
Plz
anonymous
  • anonymous
fine
anonymous
  • anonymous
what can I help you ? `
geerky42
  • geerky42
How did you end up with \(\log_{x}6 = -\dfrac{1}{2}\)? Like what Loser66 said, just convert it into exponential form; \[\log_x625 = 4\quad\Longleftrightarrow\quad x^4=625\]
MTALHAHASSAN2
  • MTALHAHASSAN2
lol it is a different question
triciaal
  • triciaal
|dw:1432971723597:dw|
triciaal
  • triciaal
I wrote in exponential form then I made the power of the variable 1. maintain the balance of the equation so raised the other side to the power (-2) also rewrite with positive exponent or simple form x = 1/36
MTALHAHASSAN2
  • MTALHAHASSAN2
|dw:1433041180988:dw| where u get this 2 over 1 from
Loser66
  • Loser66
|dw:1433041431862:dw|
Loser66
  • Loser66
|dw:1433041482916:dw|
Loser66
  • Loser66
|dw:1433041509374:dw|
Loser66
  • Loser66
|dw:1433041552084:dw|
MTALHAHASSAN2
  • MTALHAHASSAN2
but why are we square rooting each side
Loser66
  • Loser66
to get rid of 1/2
triciaal
  • triciaal
@Loser66 wait a min
Loser66
  • Loser66
Yes, sir
triciaal
  • triciaal
to make the power = 1 so that the value is just the variable
Loser66
  • Loser66
@MTALHAHASSAN2 do you agree with me that if \( 2^2 =4\) then \((2^2)^2 =4^2\)
triciaal
  • triciaal
what am I doing or saying for someone to think I am a sir?
Loser66
  • Loser66
hahaha... the flower shows you are a girl, right?
triciaal
  • triciaal
2nd time in a day is a bit much
triciaal
  • triciaal
the other person said guys like flowers too even after stating my name is pat etc
triciaal
  • triciaal
anyway back to the question
Loser66
  • Loser66
@triciaal we SOLVE the problem, that means we find x such that \(log_x 6=-1/2\)
triciaal
  • triciaal
of course we did.
Loser66
  • Loser66
in this case, we have x = 1/36, let check \(log_{1/36} 6 = -1/2?\)
Loser66
  • Loser66
I hit my calculator, it says "you are right" hehehe
MTALHAHASSAN2
  • MTALHAHASSAN2
ok thnx both of you
MTALHAHASSAN2
  • MTALHAHASSAN2
thnx a lot
Loser66
  • Loser66
@triciaal any question?
triciaal
  • triciaal
@Loser66 no. I did this correctly 23 hrs ago according to this thread.

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