## MTALHAHASSAN2 one year ago Need help!! Solve a) log base x 625 =4

1. geerky42

Hint: $$\log_x625 = \dfrac{\log 625}{\log x}$$

2. geerky42

Can you handle it now?

3. Loser66

We have equivalent formulas. Those are $$log_a b= c\iff a^c =b$$

4. Loser66

like $$log_2 8 = 3 \iff 2^3 =8$$ Same as your problem, you can convert from log to exponent and solve for x

5. MTALHAHASSAN2

thnx a lot both of you

6. MTALHAHASSAN2

wait but how can we do this one

7. MTALHAHASSAN2

|dw:1432954382672:dw|

8. MTALHAHASSAN2

|dw:1432954474494:dw|

9. MTALHAHASSAN2

can someone plz help me with it

10. MTALHAHASSAN2

Plz

11. anonymous

fine

12. anonymous

13. geerky42

How did you end up with $$\log_{x}6 = -\dfrac{1}{2}$$? Like what Loser66 said, just convert it into exponential form; $\log_x625 = 4\quad\Longleftrightarrow\quad x^4=625$

14. MTALHAHASSAN2

lol it is a different question

15. triciaal

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16. triciaal

I wrote in exponential form then I made the power of the variable 1. maintain the balance of the equation so raised the other side to the power (-2) also rewrite with positive exponent or simple form x = 1/36

17. MTALHAHASSAN2

|dw:1433041180988:dw| where u get this 2 over 1 from

18. Loser66

|dw:1433041431862:dw|

19. Loser66

|dw:1433041482916:dw|

20. Loser66

|dw:1433041509374:dw|

21. Loser66

|dw:1433041552084:dw|

22. MTALHAHASSAN2

but why are we square rooting each side

23. Loser66

to get rid of 1/2

24. triciaal

@Loser66 wait a min

25. Loser66

Yes, sir

26. triciaal

to make the power = 1 so that the value is just the variable

27. Loser66

@MTALHAHASSAN2 do you agree with me that if $$2^2 =4$$ then $$(2^2)^2 =4^2$$

28. triciaal

what am I doing or saying for someone to think I am a sir?

29. Loser66

hahaha... the flower shows you are a girl, right?

30. triciaal

2nd time in a day is a bit much

31. triciaal

the other person said guys like flowers too even after stating my name is pat etc

32. triciaal

anyway back to the question

33. Loser66

@triciaal we SOLVE the problem, that means we find x such that $$log_x 6=-1/2$$

34. triciaal

of course we did.

35. Loser66

in this case, we have x = 1/36, let check $$log_{1/36} 6 = -1/2?$$

36. Loser66

I hit my calculator, it says "you are right" hehehe

37. MTALHAHASSAN2

ok thnx both of you

38. MTALHAHASSAN2

thnx a lot

39. Loser66

@triciaal any question?

40. triciaal

@Loser66 no. I did this correctly 23 hrs ago according to this thread.