## anonymous one year ago --ALGEBRA 2 Rational Expression-- (っ◔◡◔)っ ♥ Will FAN and MEDAL ♥ Need Help with 6 question assignment

1. anonymous

2. anonymous

First question I've already answered Create a rational expression to be your game piece. You may choose from the list of factors below or make your own. There must be a variable term in both the numerator and denominator. 2x/(x+4)<----- my answer

3. anonymous

This is the second Question Turn one. Flip your coin and perform the appropriate operation. Explain to the game master how to add your rational expression to the one on the correct space. Use complete sentences.

4. anonymous

@haleyelizabeth2017 i need help :x

5. haleyelizabeth2017

That is confusing... :(

6. anonymous

Yea Dx its seem simple

7. haleyelizabeth2017

Did you flip a coin?

8. anonymous

i know how to answe part of the second Q

9. anonymous

yea thats what i was gonna do, ill pick heads

10. haleyelizabeth2017

Okay!

11. anonymous

12. haleyelizabeth2017

Whaa?? Ohh!! you add it to yours!

13. anonymous

Yea, i have to explain how i add the rational expression in sntences ://

14. Loser66

On each turn, the probability of head + tail =1, right? hence, for turn one, your equation should be $$\dfrac{x+1}{2x}+\dfrac{x-1}{3x}=1$$

15. haleyelizabeth2017

eh?

16. haleyelizabeth2017

Lol you add whatever she chose to her original fraction haha :P

17. haleyelizabeth2017

So say something like "I multiplied my first fraction by the denominator of the second fraction, and multiplied the second fraction by the denominator of the first fraction. Then, since the denominators are now equal, we can add. ....." and so on :)

18. anonymous

on the picture above it says for turn one if i get heads or tails what i have to add, and for turn two (which is for question 3) has different things i have to add if i have heads or tails

19. anonymous

Ok ill do that right now cx

20. anonymous

21. haleyelizabeth2017

:) but then explain what you got. :) but don't put blah/blah. rather, I'd put blah over blah :)

22. haleyelizabeth2017

so we got common denominators right? The denominators are x+4(2x) and the numerators are 4x^2 and x^2+4x+x+4, correct?

23. anonymous

yea

24. anonymous

wait how did you get x+4? for numerator

25. anonymous

the numerator for the first one is 2x and the second numerator is x+1

26. haleyelizabeth2017

nope....we multiplied the whole fraction :)

27. anonymous

ohhhh ok, yea im just like O.o , is that the end of Q 1?

28. haleyelizabeth2017

haha yes

29. anonymous

ok im gonna draw that out so its easier to picture lol

30. anonymous

|dw:1432954316579:dw|

31. haleyelizabeth2017

yep!

32. anonymous

did i do the top right?

33. haleyelizabeth2017

wait...

34. anonymous

how would i write the bottom?

35. haleyelizabeth2017

no....

36. haleyelizabeth2017

|dw:1432954414614:dw|

37. anonymous

yea that looks way better than what i thought lol, ok basically the second Q says *Flip your coin and perform the appropriate operation. Discuss and identify any possible restrictions that exist with (or in) the resulting rational expression.* REstrictions????

38. haleyelizabeth2017

Hmm....That's where the denominator would equal 0, I believe. Because you can't have 0 as a denominator

39. anonymous

Wouldnt 0 be the restriction?

40. anonymous

ohhhh waitt i know!

41. anonymous

dont you equal x+4 to 0?

42. anonymous

wait i'm not sure, im confusing myself now >.>

43. haleyelizabeth2017

yes!

44. haleyelizabeth2017

Well, kinda

45. haleyelizabeth2017

(x+4) AND 2x to 0, but that wouldn't really work....

46. anonymous

yea thatd be kinda weird, maybe its because i didnt roll the coin again and add turn 2

47. haleyelizabeth2017

Probably haha

48. anonymous

yea that was the first step before rational lol ok im going to roll the *coin* again

49. anonymous

i mean *before retricion

50. anonymous

i pick subtract |dw:1432954954574:dw|

51. haleyelizabeth2017

Okay...so now we take our added fractions (we forgot to do that last time, so lets do that now) and subtract that

52. anonymous

|dw:1432955031259:dw|

53. haleyelizabeth2017

So what is 4x^2+x^2+4x+x+4?

54. anonymous

4x^2 + x^2.... would be 5x^2? 4x+x=5x then 4 stays the same?

55. haleyelizabeth2017

Yes!

56. anonymous

Where would that go?

57. haleyelizabeth2017

So $$\frac{5x^2+5x+4}{x+4(2x)}$$ which was what we were supposed to get for question one...we may have forgotten to add >_<

58. haleyelizabeth2017

so now multiply both fractions again by denominators....I think....I think we may be going at this wrong :'( so lemme ask mi amigo :)

59. anonymous

should we start over really quickly? I just got really confused lol we add 2x/(x+4) by (x+1)/2x..... then got the answer for Q1 the for Q2 i rolled again and suppose to subtract x/(x+3) by the answer we got from Q1 and ok! c:

60. haleyelizabeth2017

I'm so confused right now lol I keep switching back and forth between my question and yours haha :P

61. anonymous

I can solve the problems and show you, I just need help with the explaining stuff in sentences