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anonymous

  • one year ago

--ALGEBRA 2 Rational Expression-- (っ◔◡◔)っ ♥ Will FAN and MEDAL ♥ Need Help with 6 question assignment

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    First question I've already answered Create a rational expression to be your game piece. You may choose from the list of factors below or make your own. There must be a variable term in both the numerator and denominator. 2x/(x+4)<----- my answer

  3. anonymous
    • one year ago
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    This is the second Question Turn one. Flip your coin and perform the appropriate operation. Explain to the game master how to add your rational expression to the one on the correct space. Use complete sentences.

  4. anonymous
    • one year ago
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    @haleyelizabeth2017 i need help :x

  5. haleyelizabeth2017
    • one year ago
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    That is confusing... :(

  6. anonymous
    • one year ago
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    Yea Dx its seem simple

  7. haleyelizabeth2017
    • one year ago
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    Did you flip a coin?

  8. anonymous
    • one year ago
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    i know how to answe part of the second Q

  9. anonymous
    • one year ago
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    yea thats what i was gonna do, ill pick heads

  10. haleyelizabeth2017
    • one year ago
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    Okay!

  11. anonymous
    • one year ago
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    which would be add |dw:1432953692710:dw|

  12. haleyelizabeth2017
    • one year ago
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    Whaa?? Ohh!! you add it to yours!

  13. anonymous
    • one year ago
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    Yea, i have to explain how i add the rational expression in sntences ://

  14. Loser66
    • one year ago
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    On each turn, the probability of head + tail =1, right? hence, for turn one, your equation should be \(\dfrac{x+1}{2x}+\dfrac{x-1}{3x}=1\)

  15. haleyelizabeth2017
    • one year ago
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    eh?

  16. haleyelizabeth2017
    • one year ago
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    Lol you add whatever she chose to her original fraction haha :P

  17. haleyelizabeth2017
    • one year ago
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    So say something like "I multiplied my first fraction by the denominator of the second fraction, and multiplied the second fraction by the denominator of the first fraction. Then, since the denominators are now equal, we can add. ....." and so on :)

  18. anonymous
    • one year ago
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    on the picture above it says for turn one if i get heads or tails what i have to add, and for turn two (which is for question 3) has different things i have to add if i have heads or tails

  19. anonymous
    • one year ago
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    Ok ill do that right now cx

  20. anonymous
    • one year ago
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    how do i add them?

  21. haleyelizabeth2017
    • one year ago
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    :) but then explain what you got. :) but don't put blah/blah. rather, I'd put blah over blah :)

  22. haleyelizabeth2017
    • one year ago
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    so we got common denominators right? The denominators are x+4(2x) and the numerators are 4x^2 and x^2+4x+x+4, correct?

  23. anonymous
    • one year ago
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    yea

  24. anonymous
    • one year ago
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    wait how did you get x+4? for numerator

  25. anonymous
    • one year ago
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    the numerator for the first one is 2x and the second numerator is x+1

  26. haleyelizabeth2017
    • one year ago
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    nope....we multiplied the whole fraction :)

  27. anonymous
    • one year ago
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    ohhhh ok, yea im just like O.o , is that the end of Q 1?

  28. haleyelizabeth2017
    • one year ago
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    haha yes

  29. anonymous
    • one year ago
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    ok im gonna draw that out so its easier to picture lol

  30. anonymous
    • one year ago
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    |dw:1432954316579:dw|

  31. haleyelizabeth2017
    • one year ago
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    yep!

  32. anonymous
    • one year ago
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    did i do the top right?

  33. haleyelizabeth2017
    • one year ago
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    wait...

  34. anonymous
    • one year ago
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    how would i write the bottom?

  35. haleyelizabeth2017
    • one year ago
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    no....

  36. haleyelizabeth2017
    • one year ago
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    |dw:1432954414614:dw|

  37. anonymous
    • one year ago
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    yea that looks way better than what i thought lol, ok basically the second Q says *Flip your coin and perform the appropriate operation. Discuss and identify any possible restrictions that exist with (or in) the resulting rational expression.* REstrictions????

  38. haleyelizabeth2017
    • one year ago
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    Hmm....That's where the denominator would equal 0, I believe. Because you can't have 0 as a denominator

  39. anonymous
    • one year ago
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    Wouldnt 0 be the restriction?

  40. anonymous
    • one year ago
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    ohhhh waitt i know!

  41. anonymous
    • one year ago
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    dont you equal x+4 to 0?

  42. anonymous
    • one year ago
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    wait i'm not sure, im confusing myself now >.>

  43. haleyelizabeth2017
    • one year ago
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    yes!

  44. haleyelizabeth2017
    • one year ago
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    Well, kinda

  45. haleyelizabeth2017
    • one year ago
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    (x+4) AND 2x to 0, but that wouldn't really work....

  46. anonymous
    • one year ago
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    yea thatd be kinda weird, maybe its because i didnt roll the coin again and add turn 2

  47. haleyelizabeth2017
    • one year ago
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    Probably haha

  48. anonymous
    • one year ago
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    yea that was the first step before rational lol ok im going to roll the *coin* again

  49. anonymous
    • one year ago
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    i mean *before retricion

  50. anonymous
    • one year ago
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    i pick subtract |dw:1432954954574:dw|

  51. haleyelizabeth2017
    • one year ago
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    Okay...so now we take our added fractions (we forgot to do that last time, so lets do that now) and subtract that

  52. anonymous
    • one year ago
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    |dw:1432955031259:dw|

  53. haleyelizabeth2017
    • one year ago
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    So what is 4x^2+x^2+4x+x+4?

  54. anonymous
    • one year ago
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    4x^2 + x^2.... would be 5x^2? 4x+x=5x then 4 stays the same?

  55. haleyelizabeth2017
    • one year ago
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    Yes!

  56. anonymous
    • one year ago
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    Where would that go?

  57. haleyelizabeth2017
    • one year ago
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    So \(\frac{5x^2+5x+4}{x+4(2x)}\) which was what we were supposed to get for question one...we may have forgotten to add >_<

  58. haleyelizabeth2017
    • one year ago
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    so now multiply both fractions again by denominators....I think....I think we may be going at this wrong :'( so lemme ask mi amigo :)

  59. anonymous
    • one year ago
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    should we start over really quickly? I just got really confused lol we add 2x/(x+4) by (x+1)/2x..... then got the answer for Q1 the for Q2 i rolled again and suppose to subtract x/(x+3) by the answer we got from Q1 and ok! c:

  60. haleyelizabeth2017
    • one year ago
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    I'm so confused right now lol I keep switching back and forth between my question and yours haha :P

  61. anonymous
    • one year ago
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    I can solve the problems and show you, I just need help with the explaining stuff in sentences

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