anonymous
  • anonymous
--ALGEBRA 2 Rational Expression-- (っ◔◡◔)っ ♥ Will FAN and MEDAL ♥ Need Help with 6 question assignment
Mathematics
  • Stacey Warren - Expert brainly.com
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
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anonymous
  • anonymous
First question I've already answered Create a rational expression to be your game piece. You may choose from the list of factors below or make your own. There must be a variable term in both the numerator and denominator. 2x/(x+4)<----- my answer
anonymous
  • anonymous
This is the second Question Turn one. Flip your coin and perform the appropriate operation. Explain to the game master how to add your rational expression to the one on the correct space. Use complete sentences.

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anonymous
  • anonymous
@haleyelizabeth2017 i need help :x
haleyelizabeth2017
  • haleyelizabeth2017
That is confusing... :(
anonymous
  • anonymous
Yea Dx its seem simple
haleyelizabeth2017
  • haleyelizabeth2017
Did you flip a coin?
anonymous
  • anonymous
i know how to answe part of the second Q
anonymous
  • anonymous
yea thats what i was gonna do, ill pick heads
haleyelizabeth2017
  • haleyelizabeth2017
Okay!
anonymous
  • anonymous
which would be add |dw:1432953692710:dw|
haleyelizabeth2017
  • haleyelizabeth2017
Whaa?? Ohh!! you add it to yours!
anonymous
  • anonymous
Yea, i have to explain how i add the rational expression in sntences ://
Loser66
  • Loser66
On each turn, the probability of head + tail =1, right? hence, for turn one, your equation should be \(\dfrac{x+1}{2x}+\dfrac{x-1}{3x}=1\)
haleyelizabeth2017
  • haleyelizabeth2017
eh?
haleyelizabeth2017
  • haleyelizabeth2017
Lol you add whatever she chose to her original fraction haha :P
haleyelizabeth2017
  • haleyelizabeth2017
So say something like "I multiplied my first fraction by the denominator of the second fraction, and multiplied the second fraction by the denominator of the first fraction. Then, since the denominators are now equal, we can add. ....." and so on :)
anonymous
  • anonymous
on the picture above it says for turn one if i get heads or tails what i have to add, and for turn two (which is for question 3) has different things i have to add if i have heads or tails
anonymous
  • anonymous
Ok ill do that right now cx
anonymous
  • anonymous
how do i add them?
haleyelizabeth2017
  • haleyelizabeth2017
:) but then explain what you got. :) but don't put blah/blah. rather, I'd put blah over blah :)
haleyelizabeth2017
  • haleyelizabeth2017
so we got common denominators right? The denominators are x+4(2x) and the numerators are 4x^2 and x^2+4x+x+4, correct?
anonymous
  • anonymous
yea
anonymous
  • anonymous
wait how did you get x+4? for numerator
anonymous
  • anonymous
the numerator for the first one is 2x and the second numerator is x+1
haleyelizabeth2017
  • haleyelizabeth2017
nope....we multiplied the whole fraction :)
anonymous
  • anonymous
ohhhh ok, yea im just like O.o , is that the end of Q 1?
haleyelizabeth2017
  • haleyelizabeth2017
haha yes
anonymous
  • anonymous
ok im gonna draw that out so its easier to picture lol
anonymous
  • anonymous
|dw:1432954316579:dw|
haleyelizabeth2017
  • haleyelizabeth2017
yep!
anonymous
  • anonymous
did i do the top right?
haleyelizabeth2017
  • haleyelizabeth2017
wait...
anonymous
  • anonymous
how would i write the bottom?
haleyelizabeth2017
  • haleyelizabeth2017
no....
haleyelizabeth2017
  • haleyelizabeth2017
|dw:1432954414614:dw|
anonymous
  • anonymous
yea that looks way better than what i thought lol, ok basically the second Q says *Flip your coin and perform the appropriate operation. Discuss and identify any possible restrictions that exist with (or in) the resulting rational expression.* REstrictions????
haleyelizabeth2017
  • haleyelizabeth2017
Hmm....That's where the denominator would equal 0, I believe. Because you can't have 0 as a denominator
anonymous
  • anonymous
Wouldnt 0 be the restriction?
anonymous
  • anonymous
ohhhh waitt i know!
anonymous
  • anonymous
dont you equal x+4 to 0?
anonymous
  • anonymous
wait i'm not sure, im confusing myself now >.>
haleyelizabeth2017
  • haleyelizabeth2017
yes!
haleyelizabeth2017
  • haleyelizabeth2017
Well, kinda
haleyelizabeth2017
  • haleyelizabeth2017
(x+4) AND 2x to 0, but that wouldn't really work....
anonymous
  • anonymous
yea thatd be kinda weird, maybe its because i didnt roll the coin again and add turn 2
haleyelizabeth2017
  • haleyelizabeth2017
Probably haha
anonymous
  • anonymous
yea that was the first step before rational lol ok im going to roll the *coin* again
anonymous
  • anonymous
i mean *before retricion
anonymous
  • anonymous
i pick subtract |dw:1432954954574:dw|
haleyelizabeth2017
  • haleyelizabeth2017
Okay...so now we take our added fractions (we forgot to do that last time, so lets do that now) and subtract that
anonymous
  • anonymous
|dw:1432955031259:dw|
haleyelizabeth2017
  • haleyelizabeth2017
So what is 4x^2+x^2+4x+x+4?
anonymous
  • anonymous
4x^2 + x^2.... would be 5x^2? 4x+x=5x then 4 stays the same?
haleyelizabeth2017
  • haleyelizabeth2017
Yes!
anonymous
  • anonymous
Where would that go?
haleyelizabeth2017
  • haleyelizabeth2017
So \(\frac{5x^2+5x+4}{x+4(2x)}\) which was what we were supposed to get for question one...we may have forgotten to add >_<
haleyelizabeth2017
  • haleyelizabeth2017
so now multiply both fractions again by denominators....I think....I think we may be going at this wrong :'( so lemme ask mi amigo :)
anonymous
  • anonymous
should we start over really quickly? I just got really confused lol we add 2x/(x+4) by (x+1)/2x..... then got the answer for Q1 the for Q2 i rolled again and suppose to subtract x/(x+3) by the answer we got from Q1 and ok! c:
haleyelizabeth2017
  • haleyelizabeth2017
I'm so confused right now lol I keep switching back and forth between my question and yours haha :P
anonymous
  • anonymous
I can solve the problems and show you, I just need help with the explaining stuff in sentences

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