A woman looks out a window of a building. She is 94 feet above the ground. Her line of sight makes an angle of O with the building. The distance in feet of an object from the woman is modeled by the function d = 94 sec θ. How far are objects sighted at 25° and 55°?
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They want you to plug in 25 to get some number out for d. Same for 55
keep in mind that sec(theta) = 1/cos(theta)
when you get to that link, hit the "=" button to have the calculator compute the result
I got that, but when I put it into my calc, it gives me answers wayyy off. They are supposed to be something like 104 and 164 feet....I got 94.8366 and 4247.86 :(