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anonymous

  • one year ago

What is the probability of drawing three red cards, one at a time without replacement, from a standard deck of 52 cards?

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  1. adajiamcneal
    • one year ago
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    wouldnt it be 3/26 ? because theres either red or black cards which means 26 cards are red 26 are black. but they're asking for 3 different cards. im just assuming

  2. anonymous
    • one year ago
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    3/52 2/17 1/8 75/676 are the options

  3. kobeni-chan
    • one year ago
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    adajia is right on the 3 part, but it's still talking about the chances of picking those three from the deck of 52 cards.

  4. kobeni-chan
    • one year ago
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    @Catseyeglint911

  5. adajiamcneal
    • one year ago
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    ohhhhhh ok lol i read it as 3 cards out of the red cards lol my bad

  6. anonymous
    • one year ago
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    Sorry, guys. I'm doing 3 things at once.

  7. anonymous
    • one year ago
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    I know the 3 out of 26 part and the 3 out of 52 but do you know if there is something else?

  8. kobeni-chan
    • one year ago
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    Lol thats ok adajia. And well I would assume that the answer would be 3/52 but sometimes probability is confusing so let me look in my notes.

  9. adajiamcneal
    • one year ago
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    what do you mean but something else? i mean you can split it 7 different ways if you base it off of the faces meaning king queen jack spaid heart etc i agree with kobeni the answer is 3/52

  10. kobeni-chan
    • one year ago
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    oh waiiiitttt

  11. anonymous
    • one year ago
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    So we have 26C3 and 52C3 I just didn't know if there was another combination I had to solve

  12. adajiamcneal
    • one year ago
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    8 ways my bad i forgot to count the ace lol

  13. kobeni-chan
    • one year ago
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    Half of the cards in the deck are red. So the probability of picking out one red card is 1/2. I think if you wanted to see the prob. for picking three consecutive cards like that, you would multiply the denominator by 3. So I actually think its 1/8 now.

  14. anonymous
    • one year ago
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    Do you know if the "without replacement" has any effect on the answer?

  15. adajiamcneal
    • one year ago
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    no they just mean like if you take a card out and then place it back into the deck so no it shouldnt have any effect on it

  16. kobeni-chan
    • one year ago
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    Oh wait argh. I multiplied the probabilities 26/52, 25/52, and 24/52 and got 75/676. That's probably in regards to the ''w/o replacement'' because the number of red cards in the deck decreases by one each time you take one out.

  17. kobeni-chan
    • one year ago
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    It'll have an effect on it because if you put the card back, that's another 1/52 chance that you'll pick up that red card.

  18. adajiamcneal
    • one year ago
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    oh yeah duhh. lol kobeni seems to know what shes talking about so ill just let her handle it from here haha

  19. kobeni-chan
    • one year ago
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    aww its seriously alright lol. I had a lot of trouble with probability but I'm glad i finally figured it out c:

  20. anonymous
    • one year ago
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    Wait...so wouldn't it be 26/52, 25/51, and 24/50 since cards are being taken out of the deck as well?

  21. kobeni-chan
    • one year ago
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    If I was the type f person to curse, this is when I would do it. That's right lol... you'll want to multiply all three of those fractions to get the *true* answer.

  22. anonymous
    • one year ago
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    26/52, 25/51, and 24/50 Okay multiplying these all together I got 15600/132600 = 2/17 And don't worry about it. You're fine. :)

  23. kobeni-chan
    • one year ago
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    Ok o_o lol that should be right, now.

  24. anonymous
    • one year ago
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    Thank you. :)

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