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haleyelizabeth2017
 one year ago
In Buenos Aires, Argentina, the average monthly temperature is highest in January and lowest in July, ranging from 83 degrees Fahrenheit to 57 degrees Fahrenheit. Write a cosine function that models the change in temperature according to the month of the year.
How can you find the amplitude?
What part of the problem describes the length of the cycles?
haleyelizabeth2017
 one year ago
In Buenos Aires, Argentina, the average monthly temperature is highest in January and lowest in July, ranging from 83 degrees Fahrenheit to 57 degrees Fahrenheit. Write a cosine function that models the change in temperature according to the month of the year. How can you find the amplitude? What part of the problem describes the length of the cycles?

This Question is Closed

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.1I got the amplitude....it's 13, but I'm not sure about the rest. Is it 70+13 cos ____ because 70 is where the middle of the graph is....

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.113 is definitely the amplitude and y = 70 is the midline

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1what is the period or length of each cycle?

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.1erm...not sure in this case....uno momento

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.1\(\pi/6\) because there are 6 months in between January and July, which are the min and max values.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1well the period is actually 12 months since things repeat themselves each season (more or less) so B = 2pi/T B = 2pi/12 B = pi/6 so you have the pi/6 correct but pi/6 isn't the period. It's the coefficient for the t value

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1So the function is \[\Large y = 70+13\cos\left(\frac{\pi}{6}t\right)\] y = average temperature at month t

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.1Ah...I think we missed something...in the back of the book, it says that \(\frac{\pi}{6}\) is the coefficient for (x1), where x is the month of the year. I have to explain everything I do and it's my last question...any idea how they got that?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1the (x1), instead of just x, is to allow x to start at 1 instead of 0 notice how x1 = 0 when x = 1

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1\[\Large y = 70+13\cos\left(\frac{\pi}{6}x\right) ... \text{ x starts at x = 0}\] \[\Large y = 70+13\cos\left(\frac{\pi}{6}(x1)\right) ... \text{ x starts at x = 1}\] x = month number y = avg temp

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.1Oh! Duh! *face palm*

haleyelizabeth2017
 one year ago
Best ResponseYou've already chosen the best response.1Again, thank you very much. You're a lot of help lol

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1you're welcome
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