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Triangle ABC has been rotated 90° to create triangle DEF. Using the image below, prove that perpendicular lines have opposite and reciprocal slopes. You must show all of your work to receive credit.
find the slope of both lines
If the slope of the first line is 5 then the perpendicular line will be the negative reciprocal which is -1/5
Find the slope for line BC first
Do you know how to do that?
May you remind me how it is done @10115658 . It is getting late where I am currently and my brain is sort of dead. I'm trying to take notes for an exam at the moment so just trying to see how it is solved and write it down.
Pick 2 points on the line
C and B?
Or you mean within the line?
within the line, i'll pick the first one (1,1)
I suppose we can do (2,2) as well?
i don't think that's a point on the line
what are the coordinates for point B
oh wait you confused me.
now we use the slope formula, rise/run
1 would be the slope?
wait, i think i did that wrong too.
4/3 is correct
what would be the negative reciprocal of that?
I apologize, I have not had much time to rest so I see myself making a lot of mistakes.
you don't have to apologize, happens all the time
ok, what is the reciprocal of 4/3?
i'm getting -0.0833333333 according to google for negative reciprocal.
and then the reciprocal would be 0.08. unless of course there's a formula i'm not remembering.
you don't need a calculator for this
Remind me how we determine it then if you would? Haha
.. -facepalm- 3/4 .75
now make it negative
so would it be the same case for negative reciprocal? -3/4 -.75?
ok, so now we find the slope of the other line. If the slope is -3/4 then we know the lines are perpendicular
so we are looking at EF now?
yes. So do the same thing we did before
First find 2 points
f is -1,1, e is -5, 4. just from that, i already know they are indeed perpendicular.
yep (4-1)/(-5-(-1)) = -3/4
Is it that simple to answer the question? Oh my lord, I feel dumb.
once you understand it its simple, same with all math i guess