----♥Algebra 2 Help♥------
♥How do I add these rational expressions O.o♥
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- anonymous

- schrodinger

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- anonymous

##### 1 Attachment

- kobeni-chan

I believe that you'll be using cross multiplication and the distributive property :)

- anonymous

So 2x times 2x? and x+4 times x+1?

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- kobeni-chan

Yep

- anonymous

I'm gonna solve that and show you c:

- kobeni-chan

Okies ^_^

- kobeni-chan

Oh wait...

- anonymous

I looked up the answer on Wolfram and it looks different O.o

- anonymous

##### 1 Attachment

- kobeni-chan

I forgot that you use cross multiplication to see if fractions are equal... >_<
Since the numerator on the first fraction and the denominator on the second fraction are both 2x, I think you need to cancel them out.

- anonymous

thats the answer, but i need to explain in sentcnces how i got there and ok c:

- anonymous

the image above your reply is the answer

- kobeni-chan

Ah ok. When I cross multiplied, I got 4x^2 for the first num. and second denom., and x^2 + 5x + 4 when multiplying the other values. It looks like in the answer, they added the two to get the answer's numerator.

- anonymous

How would they get whats on the numerator?

- kobeni-chan

I'm looking at this right now: http://www.purplemath.com/modules/rtnladd.htm
About halfway down the page, under 'The process works similarly for rationals.', I think its talking about this kind of thing.

- anonymous

ok i opened up the page, just waiting for it to load c:

- anonymous

This is confusing .-. :x

- kobeni-chan

Ok :) What I figured out so far is that in the answer, the denominator is 2x(x+4), which is the common denominator for 2x and x+4. You multiply x+4 (denom. of 1st fraction) by 2x, and do the same to its numerator. Then, you'll multiply 2x (denom. of 2nd fraction) by (x+4) (without distributing) and do that to the numerator too.
Does that makes sense maybe?

- anonymous

the denomator looks easy but i dont get how the numerator came out like that

- kobeni-chan

Once the denominators are the same, you can just add the numerators like a regular adding problem. Like, 3/5 + 1/5 = 4/5. The numerator's just complicated-looking because there was multiplication in the numerators when making a common denominator.

- anonymous

the message befor this one you said to add the denomator with the numerator?

- anonymous

2x(x+4)

- kobeni-chan

Well you're not adding the denominator to the numerator, if that's what you meant.
Here: with the first fraction, you have 2x/(x+4).
To make that denominator into 2x(x+4), you need to multiply the denominator by 2x.
This will look like 2x(x+4).
Since you multiplied a value in the denominator, you need to do the same to the numerator.
So what will the first fraction be?

- anonymous

2x(x+1) or would it be (x+1)2x

- kobeni-chan

Well we're just looking at the first fraction for now. You need to multiply 2x (numerator of 1st fraction) by 2x, since we multiplied that fraction's denominator by it.

- anonymous

this is making my mind hurt lol Ill get help on here tommorow c: or monday

- kobeni-chan

Oh I'm sorry :( ok I hope you feel better and have better luck with someone else! lol

- anonymous

Its ok algebra 2 is mind tripping sometimes lol

- kobeni-chan

Lol I know that feel. I'm cramming to get work done by Wednesday ;-;

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