anonymous
  • anonymous
----♥Algebra 2 Help♥------ ♥How do I add these rational expressions O.o♥ (っ◔◡◔)っ (っ◔◡◔)っ (っ◔◡◔)っ (っ◔◡◔)っ
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
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kobeni-chan
  • kobeni-chan
I believe that you'll be using cross multiplication and the distributive property :)
anonymous
  • anonymous
So 2x times 2x? and x+4 times x+1?

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kobeni-chan
  • kobeni-chan
Yep
anonymous
  • anonymous
I'm gonna solve that and show you c:
kobeni-chan
  • kobeni-chan
Okies ^_^
kobeni-chan
  • kobeni-chan
Oh wait...
anonymous
  • anonymous
I looked up the answer on Wolfram and it looks different O.o
anonymous
  • anonymous
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kobeni-chan
  • kobeni-chan
I forgot that you use cross multiplication to see if fractions are equal... >_< Since the numerator on the first fraction and the denominator on the second fraction are both 2x, I think you need to cancel them out.
anonymous
  • anonymous
thats the answer, but i need to explain in sentcnces how i got there and ok c:
anonymous
  • anonymous
the image above your reply is the answer
kobeni-chan
  • kobeni-chan
Ah ok. When I cross multiplied, I got 4x^2 for the first num. and second denom., and x^2 + 5x + 4 when multiplying the other values. It looks like in the answer, they added the two to get the answer's numerator.
anonymous
  • anonymous
How would they get whats on the numerator?
kobeni-chan
  • kobeni-chan
I'm looking at this right now: http://www.purplemath.com/modules/rtnladd.htm About halfway down the page, under 'The process works similarly for rationals.', I think its talking about this kind of thing.
anonymous
  • anonymous
ok i opened up the page, just waiting for it to load c:
anonymous
  • anonymous
This is confusing .-. :x
kobeni-chan
  • kobeni-chan
Ok :) What I figured out so far is that in the answer, the denominator is 2x(x+4), which is the common denominator for 2x and x+4. You multiply x+4 (denom. of 1st fraction) by 2x, and do the same to its numerator. Then, you'll multiply 2x (denom. of 2nd fraction) by (x+4) (without distributing) and do that to the numerator too. Does that makes sense maybe?
anonymous
  • anonymous
the denomator looks easy but i dont get how the numerator came out like that
kobeni-chan
  • kobeni-chan
Once the denominators are the same, you can just add the numerators like a regular adding problem. Like, 3/5 + 1/5 = 4/5. The numerator's just complicated-looking because there was multiplication in the numerators when making a common denominator.
anonymous
  • anonymous
the message befor this one you said to add the denomator with the numerator?
anonymous
  • anonymous
2x(x+4)
kobeni-chan
  • kobeni-chan
Well you're not adding the denominator to the numerator, if that's what you meant. Here: with the first fraction, you have 2x/(x+4). To make that denominator into 2x(x+4), you need to multiply the denominator by 2x. This will look like 2x(x+4). Since you multiplied a value in the denominator, you need to do the same to the numerator. So what will the first fraction be?
anonymous
  • anonymous
2x(x+1) or would it be (x+1)2x
kobeni-chan
  • kobeni-chan
Well we're just looking at the first fraction for now. You need to multiply 2x (numerator of 1st fraction) by 2x, since we multiplied that fraction's denominator by it.
anonymous
  • anonymous
this is making my mind hurt lol Ill get help on here tommorow c: or monday
kobeni-chan
  • kobeni-chan
Oh I'm sorry :( ok I hope you feel better and have better luck with someone else! lol
anonymous
  • anonymous
Its ok algebra 2 is mind tripping sometimes lol
kobeni-chan
  • kobeni-chan
Lol I know that feel. I'm cramming to get work done by Wednesday ;-;

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