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anonymous

  • one year ago

given the triangle below, find sec X, tan X, and cos Z in fraction form (pic included)

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  1. anonymous
    • one year ago
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    |dw:1432958949158:dw|

  2. anonymous
    • one year ago
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    Hello :)

  3. anonymous
    • one year ago
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    are you there?

  4. anonymous
    • one year ago
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    yeah

  5. anonymous
    • one year ago
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    lol do you know how to do this one?

  6. anonymous
    • one year ago
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    yep

  7. anonymous
    • one year ago
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    are you familiar with SOH CAH TOA?

  8. anonymous
    • one year ago
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    sort of

  9. anonymous
    • one year ago
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    ok, lets find cos Z first

  10. anonymous
    • one year ago
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    how?

  11. anonymous
    • one year ago
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    cos z= adj/hyp

  12. anonymous
    • one year ago
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    |dw:1432959576632:dw|

  13. anonymous
    • one year ago
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    so 15 / 25? or?

  14. anonymous
    • one year ago
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    thats right

  15. anonymous
    • one year ago
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    .6

  16. anonymous
    • one year ago
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    they said in fraction form so 15/25 or 3/5 work

  17. anonymous
    • one year ago
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    oh.. okay so cos z = 3/5 .. whats next? :/

  18. anonymous
    • one year ago
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    find tanx

  19. anonymous
    • one year ago
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    how?

  20. anonymous
    • one year ago
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    Find the missing side

  21. anonymous
    • one year ago
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    use pythagorean

  22. anonymous
    • one year ago
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    Do you know how to do that

  23. anonymous
    • one year ago
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    so a^2 + b ^ = c^?

  24. anonymous
    • one year ago
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    thats right

  25. anonymous
    • one year ago
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    25 = c 625 - 225 = 400 20

  26. anonymous
    • one year ago
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    good job now find tanx

  27. anonymous
    • one year ago
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    25 / 20 or 20/ 25?

  28. anonymous
    • one year ago
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    opposite / adjacent

  29. anonymous
    • one year ago
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    15 / 20 3/ 4

  30. anonymous
    • one year ago
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    well done

  31. anonymous
    • one year ago
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    what about secx

  32. anonymous
    • one year ago
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    now sec x

  33. anonymous
    • one year ago
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    whats the formula?

  34. anonymous
    • one year ago
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    secx = 1/cosx

  35. anonymous
    • one year ago
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    20 / 15?

  36. anonymous
    • one year ago
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    how do i do that?

  37. anonymous
    • one year ago
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    is cos opposite/adjacent adjacent/hypotenuse or opposite/hypotenuse

  38. anonymous
    • one year ago
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    opposite / hypotenuse

  39. anonymous
    • one year ago
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    nope

  40. anonymous
    • one year ago
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    Try to remember SOH CAH TOA

  41. anonymous
    • one year ago
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    SOH: sin = opposite/hypotenuse

  42. anonymous
    • one year ago
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    CAH: cos = adjacent/hypotenuse

  43. anonymous
    • one year ago
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    TOA: tan = opposite/adjacent

  44. anonymous
    • one year ago
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    so 15 / 25?

  45. anonymous
    • one year ago
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    nope

  46. anonymous
    • one year ago
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    remember sec = 1/cos

  47. anonymous
    • one year ago
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    the hypotenuse is 25?

  48. anonymous
    • one year ago
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    cos is adjacent/hypotenuse

  49. anonymous
    • one year ago
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    take the reciprocal to get hypotenuse/adjacent

  50. anonymous
    • one year ago
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    secx=hypotenuse/adjacent

  51. anonymous
    • one year ago
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    |dw:1432960516695:dw|

  52. anonymous
    • one year ago
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    Don't forget, we're looking at x

  53. anonymous
    • one year ago
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    so 20 /25 or 25 / 20?

  54. anonymous
    • one year ago
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    hyotenuse/adjacent

  55. anonymous
    • one year ago
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    25 / 20

  56. anonymous
    • one year ago
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    5/4, good job

  57. anonymous
    • one year ago
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    awesome! thanks :)

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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