anonymous
  • anonymous
given the triangle below, find sec X, tan X, and cos Z in fraction form (pic included)
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
|dw:1432958949158:dw|
anonymous
  • anonymous
Hello :)
anonymous
  • anonymous
are you there?

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anonymous
  • anonymous
yeah
anonymous
  • anonymous
lol do you know how to do this one?
anonymous
  • anonymous
yep
anonymous
  • anonymous
are you familiar with SOH CAH TOA?
anonymous
  • anonymous
sort of
anonymous
  • anonymous
ok, lets find cos Z first
anonymous
  • anonymous
how?
anonymous
  • anonymous
cos z= adj/hyp
anonymous
  • anonymous
|dw:1432959576632:dw|
anonymous
  • anonymous
so 15 / 25? or?
anonymous
  • anonymous
thats right
anonymous
  • anonymous
.6
anonymous
  • anonymous
they said in fraction form so 15/25 or 3/5 work
anonymous
  • anonymous
oh.. okay so cos z = 3/5 .. whats next? :/
anonymous
  • anonymous
find tanx
anonymous
  • anonymous
how?
anonymous
  • anonymous
Find the missing side
anonymous
  • anonymous
use pythagorean
anonymous
  • anonymous
Do you know how to do that
anonymous
  • anonymous
so a^2 + b ^ = c^?
anonymous
  • anonymous
thats right
anonymous
  • anonymous
25 = c 625 - 225 = 400 20
anonymous
  • anonymous
good job now find tanx
anonymous
  • anonymous
25 / 20 or 20/ 25?
anonymous
  • anonymous
opposite / adjacent
anonymous
  • anonymous
15 / 20 3/ 4
anonymous
  • anonymous
well done
anonymous
  • anonymous
what about secx
anonymous
  • anonymous
now sec x
anonymous
  • anonymous
whats the formula?
anonymous
  • anonymous
secx = 1/cosx
anonymous
  • anonymous
20 / 15?
anonymous
  • anonymous
how do i do that?
anonymous
  • anonymous
is cos opposite/adjacent adjacent/hypotenuse or opposite/hypotenuse
anonymous
  • anonymous
opposite / hypotenuse
anonymous
  • anonymous
nope
anonymous
  • anonymous
Try to remember SOH CAH TOA
anonymous
  • anonymous
SOH: sin = opposite/hypotenuse
anonymous
  • anonymous
CAH: cos = adjacent/hypotenuse
anonymous
  • anonymous
TOA: tan = opposite/adjacent
anonymous
  • anonymous
so 15 / 25?
anonymous
  • anonymous
nope
anonymous
  • anonymous
remember sec = 1/cos
anonymous
  • anonymous
the hypotenuse is 25?
anonymous
  • anonymous
cos is adjacent/hypotenuse
anonymous
  • anonymous
take the reciprocal to get hypotenuse/adjacent
anonymous
  • anonymous
secx=hypotenuse/adjacent
anonymous
  • anonymous
|dw:1432960516695:dw|
anonymous
  • anonymous
Don't forget, we're looking at x
anonymous
  • anonymous
so 20 /25 or 25 / 20?
anonymous
  • anonymous
hyotenuse/adjacent
anonymous
  • anonymous
25 / 20
anonymous
  • anonymous
5/4, good job
anonymous
  • anonymous
awesome! thanks :)

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