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adajiamcneal

  • one year ago

Please Help

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  1. adajiamcneal
    • one year ago
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  2. adajiamcneal
    • one year ago
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    i think its a but im not sure..

  3. anonymous
    • one year ago
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    @adajiamcneal Your answer is well :)

  4. theopenstudyowl
    • one year ago
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    I think it's 10 but I am a bit unsure...

  5. adajiamcneal
    • one year ago
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    ok thank you :) i have a couple more ..

  6. anonymous
    • one year ago
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    K let me know :)

  7. adajiamcneal
    • one year ago
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  8. adajiamcneal
    • one year ago
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    @Omar_Elboredy

  9. anonymous
    • one year ago
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    So let's take it easily and step-by-step , you have 2 polygons of the same shape and U want to compare them ... Then the easy step is to use ratio! \[\frac{ 12 }{ 40 } = \frac{ 3 }{ x }\] Then nw you have to get x in one side and othe stuff on the other side like that \[\frac{ x }{ 3 } = \frac{ 40 }{ 12 } \] Multiplying both sides by 3 : \[x = \frac{ 40 }{ 4 } = ?\] Let me know if you got it :)

  10. adajiamcneal
    • one year ago
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    B ?

  11. anonymous
    • one year ago
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    aha (y)

  12. adajiamcneal
    • one year ago
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    because 40/4 = 10 lol

  13. anonymous
    • one year ago
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    :)

  14. adajiamcneal
    • one year ago
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    c?

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  15. adajiamcneal
    • one year ago
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    @Omar_Elboredy

  16. anonymous
    • one year ago
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    1 cm = 10 ft. then 4.7 cm = ? By criss-cross : ? = 4.7 * 10 = 47 ft :) Which will be "D" :)

  17. adajiamcneal
    • one year ago
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    b? @Omar_Elboredy

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  18. anonymous
    • one year ago
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    To find length of hypotenuse use Pythagorean theorem . Applying this to given prob. you will get : \[\sqrt{17^2 + 17^2} = 17\sqrt{2}\] Which will be C

  19. adajiamcneal
    • one year ago
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    @Omar_Elboredy idk how to do this one.. i typed it in the calculator and i dont get any of the options.

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  20. anonymous
    • one year ago
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    Could U plz show me wat U typed ! :D

  21. adajiamcneal
    • one year ago
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    lol i have a scientific calculator i typed in 7 and hit tan-1 haha

  22. anonymous
    • one year ago
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    So wat U got out ?

  23. adajiamcneal
    • one year ago
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    0.122784561 lol

  24. anonymous
    • one year ago
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    O.o See. .. First be sure that you are in the deg. mode and then type in sth like this : \[\tan^{-1} 7\] and then hit equal sign then let me know wat U get :)

  25. adajiamcneal
    • one year ago
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    it is in the degree mode and i still get the same thing

  26. anonymous
    • one year ago
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    U hit tan(7) ! :D

  27. anonymous
    • one year ago
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    U have to hit this : shift button then tan button u will get tan-1 shown on the screen :D then type 7 and show me wat U get

  28. adajiamcneal
    • one year ago
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    ohhhhhhh its c lol i feel dumb -.-

  29. anonymous
    • one year ago
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    :D

  30. adajiamcneal
    • one year ago
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    ok if i need more ill tagg you in a different question :) thank you

  31. anonymous
    • one year ago
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    If U wanna pm me it's ok :)

  32. adajiamcneal
    • one year ago
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    @ayyookyndall

  33. anonymous
    • one year ago
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    K let me see wat's next :D

  34. adajiamcneal
    • one year ago
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  35. anonymous
    • one year ago
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    mmmmm I couldn't figure out what's wrong with that question .. I think it's 40 cm^2 but the answer is not shown ! :D

  36. anonymous
    • one year ago
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    Aha I got the trick :D You have to calculate the missing portion of the base which will be 8 & \[\frac{ 4 }{ \sin(45) } = 4\sqrt{2}\] Then apply the rule you will get sth near "C" :)

  37. adajiamcneal
    • one year ago
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  38. anonymous
    • one year ago
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    For reflection about the y-axis you have think about it like you a mirror on the y-axis which means that the y-coordinates for each point will be the same the only change will be with the sign of x-coordinates for each point So wat will be the answer ? :)

  39. adajiamcneal
    • one year ago
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    D?

  40. anonymous
    • one year ago
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    By this you changed the sign of both x-coordinates and y-coordinates ... And we only want to change the sign of x's

  41. ayyookyndall
    • one year ago
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    Its C, correct?

  42. anonymous
    • one year ago
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    Yes :)

  43. anonymous
    • one year ago
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    Take this as a rule : If you wanna reflect about x-axis just change the sign of y-coordinates only If you wanna reflect about y-axis just change the sign of x-coordinates only If you wanna reflect about the origin just think you do this in two steps .. one about x-axis and the other is about the y-axis :)

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  44. adajiamcneal
    • one year ago
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  45. anonymous
    • one year ago
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    This includes two separate types of data : Angle and length(magnitude) The angle is calculated like this : you know from trig rules that SOH CAH TOA >> \[\sin(x) = \frac{ Opposite }{ Hypotenuse } , \cos(x) = \frac{ Adjacent }{ Hypotenuse } , \tan(x) = \frac{ Opposite }{ Adjacent }\] Then you nw have wat for x ? Opposite which is -12 and Adjacent which is - 26 , then use which rule ? We use tan , the this will be sth like this : \[\tan(x) = \frac{ -12 }{ -26 }\] and to get x we have to do tan-1 ! :D then x will bet : \[x = \tan^{-1} (\frac{ -12 }{ -26 } = 24.775\] which is nearly 25 deg the nw for the direction : its west south (y) Now wat ? :D It's magnitude

  46. anonymous
    • one year ago
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    So let's calculate magnitude , as you know this is a right-angled triangle , so to get the length of hypotenuse we use the Pythagorean theory which is : \[a^2 = b^2 + c^2\] we here have b and c |dw:1432965278834:dw| so to get a we apply the rule and we simply get \[a^2 = 820\] to get a we take the square root for both sides in which we will get \[a = 29\] so the answer will be ? Let me know wat you figured out :D

  47. adajiamcneal
    • one year ago
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    D

  48. anonymous
    • one year ago
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    What is the value of angle (x) ?

  49. adajiamcneal
    • one year ago
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    24.775

  50. anonymous
    • one year ago
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    which is 25 ok :D Then by this we exclude D and B , now what is the direction ?

  51. adajiamcneal
    • one year ago
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    west south

  52. adajiamcneal
    • one year ago
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    oh so its a?

  53. anonymous
    • one year ago
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    Exactly ! :D

  54. adajiamcneal
    • one year ago
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    ok im done :) kyndall might need help though so can you please help her ?

  55. anonymous
    • one year ago
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    K no prob. feel free to ask me anytime :)

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