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anonymous
 one year ago
Matt sells burgers and sandwiches. The daily cost of making burgers is $520 more than the difference between the square of the number of burgers sold and 30 times the number of burgers sold. The daily cost of making sandwiches is modeled by the following equation:
C(x) = 2x2  40x + 300
C(x) is the cost in dollars of selling x sandwiches.
Which statement best compares the minimum daily cost of making burgers and sandwiches
anonymous
 one year ago
Matt sells burgers and sandwiches. The daily cost of making burgers is $520 more than the difference between the square of the number of burgers sold and 30 times the number of burgers sold. The daily cost of making sandwiches is modeled by the following equation: C(x) = 2x2  40x + 300 C(x) is the cost in dollars of selling x sandwiches. Which statement best compares the minimum daily cost of making burgers and sandwiches

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It is greater for sandwiches than burgers because the approximate minimum cost is $250 for burgers and $292 for sandwiches. It is greater for sandwiches than burgers because the approximate minimum cost is $100 for burgers and $295 for sandwiches. It is greater for burgers than sandwiches because the approximate minimum cost is $295 for burgers and $100 for sandwiches. It is greater for burgers than sandwiches because the approximate minimum cost is $292 for burgers and $250 for sandwiches

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0I am helping ! this is what I have so far

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1432963888967:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1432964031859:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0the equation written with the question is for sandwiches when x = 0 then the cost = 300

Jack1
 one year ago
Best ResponseYou've already chosen the best response.2tricalls back, she's doin awesome man, jus be patient

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1432964510506:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0sorry, i'm missing something (more than just sleep)

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0what is the value of x when the costs are equal @Jack1 sure always feel free to join in

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So, the answer is: It is greater for burgers than sandwiches because the approximate minimum cost is $292 for burgers and $250 for sandwiches because it is about 1/2 the total when I make x=0 ? @triciaal & @Jack1

Jack1
 one year ago
Best ResponseYou've already chosen the best response.2The daily cost (C(z))of making burgers (z) is $520 more than the difference between the square of the number of burgers (z^2) sold and 30 times the number of burgers sold (30z). so as an equation for burgers: C(z) = z^2  30z + 520

Jack1
 one year ago
Best ResponseYou've already chosen the best response.2The daily cost of making sandwiches is: C(x) = 2x^2  40x + 300

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0compare the cost when x = 4?

Jack1
 one year ago
Best ResponseYou've already chosen the best response.2cost (C) to make sandwiches (x) \(\large C(x) = 2x^2  40x + 300\) this equation is a parabola, lowest cost is at lowest point on parabola = turning point turning point is when the gradient = 0 gradient of a parabola is the derivative \(\large C(x) = 2x^2  40x + 300\) \(\large C'(x) = 4x  40 \) so when gradient ( C'(x) ) = 0 \(\large 0 = 4x  40 \) \(\large 40 = 4x \) \(\large x = 10 \) so lowest cost is when x = 10 (number of sandwiches = 10) what cost (C) is that tho? \(\large C(x) = 2x^2  40x + 300\) \(\large C(10) = 2(10)^2  40(10) + 300\) \(\large C = u solve this ???\) @zayyyc_

Jack1
 one year ago
Best ResponseYou've already chosen the best response.2then do the same for burgers (z) then you'll have ur answer ;)

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0@Jack1 so 10 sandwiches and 4 burgers?

Jack1
 one year ago
Best ResponseYou've already chosen the best response.2i got 15 burgers for that parabola min point...?

Jack1
 one year ago
Best ResponseYou've already chosen the best response.2cool @zayyyc_ so what did u get as the min cost for sangers, and whats the min cost for burgers?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1432965929266:dw

Jack1
 one year ago
Best ResponseYou've already chosen the best response.2yep, me too: $295 for 15 burgers is it's min, and $100 for 10x sandwiches is it's minimum cost... hope this helps?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It is greater for sandwiches than burgers because the approximate minimum cost is $250 for burgers and $292 for sandwiches ?

Jack1
 one year ago
Best ResponseYou've already chosen the best response.2nah man, sorry we know the min cost for sandwiches is $100 and the min cost for burgers is $295 so the only one that fits is C, yeah? It is greater for burgers than sandwiches because the approximate minimum cost is $295 for burgers and $100 for sandwiches.

Jack1
 one year ago
Best ResponseYou've already chosen the best response.2you following ok tho or need something explained a bit more? s 'cool if u do hey
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