Trig :)

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Coz f(x) have one half of the period of g(x) , f(x) have a period of pi. and f(pi/4) = 4 and they are both sine waves. f(0)=0 and because of period , x=pi f(pi) = 0 again. so f(x) = 4sin(2x)
we can assume f(x) =ASin(Bx) +C where A,B,C are variables x=0, f(x)=0 and when x=pi/4 f(x)=4 and when x= pi f(x) =0 so we can solve it for the three variables that way too

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I'm confused...
sorry i assigned f(x) as f(θ ) and g(x) as g(θ )
It's not that....
I'm just not quite understanding what I have to do :(
ok lets try from the beginning. It says both functions are sine functions. right? so f(θ ) takes the format of f(θ )= ASin(Bx)+C
I've never really learned that format....I just learned that "A" as you say is the amplitude, and B is period...what is C? O.o
Wait...that might just be for cos. Never mind...
So can you solve it now?
Lemme try.... :)
I'm just caught on the amplitude part....
Which one is amp.... pi/4 or 4?
I think 4....
yeah amplitude is 4
\(g(\theta)=2~sin~2\pi~\theta\) eh?
just relax its easy . this is a graph ok? a graph of a sin function. according to θ ,y or f(x) change ok?
Ah, yes.

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