## haleyelizabeth2017 one year ago Trig :)

1. haleyelizabeth2017

2. anonymous

Coz f(x) have one half of the period of g(x) , f(x) have a period of pi. and f(pi/4) = 4 and they are both sine waves. f(0)=0 and because of period , x=pi f(pi) = 0 again. so f(x) = 4sin(2x)

3. anonymous

we can assume f(x) =ASin(Bx) +C where A,B,C are variables x=0, f(x)=0 and when x=pi/4 f(x)=4 and when x= pi f(x) =0 so we can solve it for the three variables that way too

4. haleyelizabeth2017

I'm confused...

5. anonymous

sorry i assigned f(x) as f(θ ) and g(x) as g(θ )

6. haleyelizabeth2017

It's not that....

7. haleyelizabeth2017

I'm just not quite understanding what I have to do :(

8. anonymous

ok lets try from the beginning. It says both functions are sine functions. right? so f(θ ) takes the format of f(θ )= ASin(Bx)+C

9. haleyelizabeth2017

I've never really learned that format....I just learned that "A" as you say is the amplitude, and B is period...what is C? O.o

10. haleyelizabeth2017

Wait...that might just be for cos. Never mind...

11. anonymous

So can you solve it now?

12. haleyelizabeth2017

Lemme try.... :)

13. haleyelizabeth2017

I'm just caught on the amplitude part....

14. haleyelizabeth2017

Which one is amp.... pi/4 or 4?

15. haleyelizabeth2017

I think 4....

16. anonymous

yeah amplitude is 4

17. haleyelizabeth2017

$$g(\theta)=2~sin~2\pi~\theta$$ eh?

18. anonymous

just relax its easy . this is a graph ok? a graph of a sin function. according to θ ,y or f(x) change ok?

19. haleyelizabeth2017

Ah, yes.