haleyelizabeth2017
  • haleyelizabeth2017
Trig :)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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haleyelizabeth2017
  • haleyelizabeth2017
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anonymous
  • anonymous
Coz f(x) have one half of the period of g(x) , f(x) have a period of pi. and f(pi/4) = 4 and they are both sine waves. f(0)=0 and because of period , x=pi f(pi) = 0 again. so f(x) = 4sin(2x)
anonymous
  • anonymous
we can assume f(x) =ASin(Bx) +C where A,B,C are variables x=0, f(x)=0 and when x=pi/4 f(x)=4 and when x= pi f(x) =0 so we can solve it for the three variables that way too

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haleyelizabeth2017
  • haleyelizabeth2017
I'm confused...
anonymous
  • anonymous
sorry i assigned f(x) as f(θ ) and g(x) as g(θ )
haleyelizabeth2017
  • haleyelizabeth2017
It's not that....
haleyelizabeth2017
  • haleyelizabeth2017
I'm just not quite understanding what I have to do :(
anonymous
  • anonymous
ok lets try from the beginning. It says both functions are sine functions. right? so f(θ ) takes the format of f(θ )= ASin(Bx)+C
haleyelizabeth2017
  • haleyelizabeth2017
I've never really learned that format....I just learned that "A" as you say is the amplitude, and B is period...what is C? O.o
haleyelizabeth2017
  • haleyelizabeth2017
Wait...that might just be for cos. Never mind...
anonymous
  • anonymous
So can you solve it now?
haleyelizabeth2017
  • haleyelizabeth2017
Lemme try.... :)
haleyelizabeth2017
  • haleyelizabeth2017
I'm just caught on the amplitude part....
haleyelizabeth2017
  • haleyelizabeth2017
Which one is amp.... pi/4 or 4?
haleyelizabeth2017
  • haleyelizabeth2017
I think 4....
anonymous
  • anonymous
yeah amplitude is 4
haleyelizabeth2017
  • haleyelizabeth2017
\(g(\theta)=2~sin~2\pi~\theta\) eh?
anonymous
  • anonymous
just relax its easy . this is a graph ok? a graph of a sin function. according to θ ,y or f(x) change ok?
haleyelizabeth2017
  • haleyelizabeth2017
Ah, yes.

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