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Math2400
 one year ago
determine the sum of this series...i thought it was divergent but I guess it diverges cuz it says that it's not divergent
Math2400
 one year ago
determine the sum of this series...i thought it was divergent but I guess it diverges cuz it says that it's not divergent

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Math2400
 one year ago
Best ResponseYou've already chosen the best response.1\[\sum_{n=1}^{\infty} \frac{ (3)^{n1} }{ 5^n}\]

Math2400
 one year ago
Best ResponseYou've already chosen the best response.1@jim_thompson5910 would u be able to help me on this please?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3As a start, write the fraction in single exponent

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3\[\sum_{n=1}^{\infty} \frac{ (3)^{n1} }{ 5^n} = \sum_{n=1}^{\infty} \frac{ (3)^{n} }{ (3)5^n} = \frac{1}{3}\sum_{n=1}^{\infty} \left(\frac{ 3 }{ 5}\right)^n\]

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3next recall geometric series

Math2400
 one year ago
Best ResponseYou've already chosen the best response.1what would be r? this is where I'm confused

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3r = the stuff under the exponent = 3/5

Math2400
 one year ago
Best ResponseYou've already chosen the best response.1and for a i just plug in 1 into the equation?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3there is no equation

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3for "a", just plugin n=1 into the general term of series

Math2400
 one year ago
Best ResponseYou've already chosen the best response.1that's what i mean haha :)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3i kno, just making sure you see the difference between "equation" and "expression"

Math2400
 one year ago
Best ResponseYou've already chosen the best response.1okay i plugged everything in but it's zero??

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3what do you get for first term, a ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3Ah no, below is our slightly massaged series : \[\frac{1}{3}\color{blue}{\sum_{n=1}^{\infty} \left(\frac{ 3 }{ 5}\right)^n}\] plugin \(n=1\), you get \(a_1 = \frac{3}{5} \) \(r = \frac{3}{5}\) so the infinite sum is \[\dfrac{3/5}{1(3/5)}\] simplify

Math2400
 one year ago
Best ResponseYou've already chosen the best response.1that's still not right tho haha

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3looks good, don't forget that 1/3 in front
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