To solve the system of equations below, Zach isolated x2 in the first equation and then substituted it into the second equation. What was the resulting equation?

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To solve the system of equations below, Zach isolated x2 in the first equation and then substituted it into the second equation. What was the resulting equation?

Mathematics
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http://media.apexlearning.com/Images/201011/29/c0be4b3b-9dcc-45a7-8483-d14f395ca1fc.gif
the same response you had earlier
none answered it

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Other answers:

you have the expression for x^2 from the first equation. go ahead and use this expression in the second equation every time you see x^2 then solve the equation with the one variable
I just checked
don't be ungrateful!!! whenever you need more help just let the person know you need a bit more
@10115658 was the one who helped you and I gave a medal
what is the second equation?
you might want to use the "draw"
do you want me to help you to finish this or not?
sorry i was in the Bathroom
ok fine leave this open so someone else will was just about to leave
what is the second equation? and do you know how to get rid of the fraction?
ive been stuck on this all day
single out the x variable?
work with me to get you out the rut
again what is the second equation?
|dw:1432968481833:dw|
x^2/16-y^2/9=1
yes
now can you get rid of the fraction?
do you remember how you would do something like |dw:1432968632299:dw|
you can let me know when you are back if you want me to continue
im writing it out
on paper
-2/15?
GCF
sorry im coming into this late give me a sec...
its fine ill take all the help
\(\large x^2 + y^2 = 25\) so whoever it was in the q isolated x^2 from the 1st equation... yeah? so would look like \(\large x^2 + y^2 = 25\) \(\large x^2 = 25 - y^2\) I'm proly goin whay too slow, but you with me so far?
ya
cool, so next they subbed this : \(\large \color{red} {x^2 = 25 - y^2}\) into the 2nd equation: \(\huge \frac{x^2}{16} - \frac{y^2}9 = 1\) so would look something like this: \(\huge \frac{x^2}{16} - \frac{y^2}9 = 1\) \(\huge \frac{\color{red} {25 - y^2}}{16} - \frac{y^2}9 = 1\) so u still with me man, any q's so far?
i got it!
i wrote down all the steps for it
cool man... so that's the resulting equation... u can solve it if u want, but the above's pretty much all they're lookin for in the q
oksy thanks so much dude!
no worries man ;)

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