anonymous
  • anonymous
To solve the system of equations below, Zach isolated x2 in the first equation and then substituted it into the second equation. What was the resulting equation?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
http://media.apexlearning.com/Images/201011/29/c0be4b3b-9dcc-45a7-8483-d14f395ca1fc.gif
triciaal
  • triciaal
the same response you had earlier
anonymous
  • anonymous
none answered it

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

triciaal
  • triciaal
you have the expression for x^2 from the first equation. go ahead and use this expression in the second equation every time you see x^2 then solve the equation with the one variable
triciaal
  • triciaal
I just checked
triciaal
  • triciaal
don't be ungrateful!!! whenever you need more help just let the person know you need a bit more
triciaal
  • triciaal
@10115658 was the one who helped you and I gave a medal
triciaal
  • triciaal
what is the second equation?
triciaal
  • triciaal
you might want to use the "draw"
triciaal
  • triciaal
do you want me to help you to finish this or not?
anonymous
  • anonymous
sorry i was in the Bathroom
triciaal
  • triciaal
ok fine leave this open so someone else will was just about to leave
triciaal
  • triciaal
what is the second equation? and do you know how to get rid of the fraction?
anonymous
  • anonymous
ive been stuck on this all day
anonymous
  • anonymous
single out the x variable?
triciaal
  • triciaal
work with me to get you out the rut
triciaal
  • triciaal
again what is the second equation?
triciaal
  • triciaal
|dw:1432968481833:dw|
anonymous
  • anonymous
x^2/16-y^2/9=1
anonymous
  • anonymous
yes
triciaal
  • triciaal
now can you get rid of the fraction?
triciaal
  • triciaal
do you remember how you would do something like |dw:1432968632299:dw|
triciaal
  • triciaal
you can let me know when you are back if you want me to continue
anonymous
  • anonymous
im writing it out
anonymous
  • anonymous
on paper
anonymous
  • anonymous
-2/15?
anonymous
  • anonymous
GCF
Jack1
  • Jack1
sorry im coming into this late give me a sec...
anonymous
  • anonymous
its fine ill take all the help
Jack1
  • Jack1
\(\large x^2 + y^2 = 25\) so whoever it was in the q isolated x^2 from the 1st equation... yeah? so would look like \(\large x^2 + y^2 = 25\) \(\large x^2 = 25 - y^2\) I'm proly goin whay too slow, but you with me so far?
anonymous
  • anonymous
ya
Jack1
  • Jack1
cool, so next they subbed this : \(\large \color{red} {x^2 = 25 - y^2}\) into the 2nd equation: \(\huge \frac{x^2}{16} - \frac{y^2}9 = 1\) so would look something like this: \(\huge \frac{x^2}{16} - \frac{y^2}9 = 1\) \(\huge \frac{\color{red} {25 - y^2}}{16} - \frac{y^2}9 = 1\) so u still with me man, any q's so far?
anonymous
  • anonymous
i got it!
anonymous
  • anonymous
i wrote down all the steps for it
Jack1
  • Jack1
cool man... so that's the resulting equation... u can solve it if u want, but the above's pretty much all they're lookin for in the q
anonymous
  • anonymous
oksy thanks so much dude!
Jack1
  • Jack1
no worries man ;)

Looking for something else?

Not the answer you are looking for? Search for more explanations.