## anonymous one year ago To solve the system of equations below, Zach isolated x2 in the first equation and then substituted it into the second equation. What was the resulting equation?

1. anonymous
2. triciaal

the same response you had earlier

3. anonymous

4. triciaal

you have the expression for x^2 from the first equation. go ahead and use this expression in the second equation every time you see x^2 then solve the equation with the one variable

5. triciaal

I just checked

6. triciaal

don't be ungrateful!!! whenever you need more help just let the person know you need a bit more

7. triciaal

@10115658 was the one who helped you and I gave a medal

8. triciaal

what is the second equation?

9. triciaal

you might want to use the "draw"

10. triciaal

do you want me to help you to finish this or not?

11. anonymous

sorry i was in the Bathroom

12. triciaal

ok fine leave this open so someone else will was just about to leave

13. triciaal

what is the second equation? and do you know how to get rid of the fraction?

14. anonymous

ive been stuck on this all day

15. anonymous

single out the x variable?

16. triciaal

work with me to get you out the rut

17. triciaal

again what is the second equation?

18. triciaal

|dw:1432968481833:dw|

19. anonymous

x^2/16-y^2/9=1

20. anonymous

yes

21. triciaal

now can you get rid of the fraction?

22. triciaal

do you remember how you would do something like |dw:1432968632299:dw|

23. triciaal

you can let me know when you are back if you want me to continue

24. anonymous

im writing it out

25. anonymous

on paper

26. anonymous

-2/15?

27. anonymous

GCF

28. Jack1

sorry im coming into this late give me a sec...

29. anonymous

its fine ill take all the help

30. Jack1

$$\large x^2 + y^2 = 25$$ so whoever it was in the q isolated x^2 from the 1st equation... yeah? so would look like $$\large x^2 + y^2 = 25$$ $$\large x^2 = 25 - y^2$$ I'm proly goin whay too slow, but you with me so far?

31. anonymous

ya

32. Jack1

cool, so next they subbed this : $$\large \color{red} {x^2 = 25 - y^2}$$ into the 2nd equation: $$\huge \frac{x^2}{16} - \frac{y^2}9 = 1$$ so would look something like this: $$\huge \frac{x^2}{16} - \frac{y^2}9 = 1$$ $$\huge \frac{\color{red} {25 - y^2}}{16} - \frac{y^2}9 = 1$$ so u still with me man, any q's so far?

33. anonymous

i got it!

34. anonymous

i wrote down all the steps for it

35. Jack1

cool man... so that's the resulting equation... u can solve it if u want, but the above's pretty much all they're lookin for in the q

36. anonymous

oksy thanks so much dude!

37. Jack1

no worries man ;)