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anonymous
 one year ago
To solve the system of equations below, Zach isolated x2 in the first equation and then substituted it into the second equation. What was the resulting equation?
anonymous
 one year ago
To solve the system of equations below, Zach isolated x2 in the first equation and then substituted it into the second equation. What was the resulting equation?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0http://media.apexlearning.com/Images/201011/29/c0be4b3b9dcc45a78483d14f395ca1fc.gif

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0the same response you had earlier

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0you have the expression for x^2 from the first equation. go ahead and use this expression in the second equation every time you see x^2 then solve the equation with the one variable

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0don't be ungrateful!!! whenever you need more help just let the person know you need a bit more

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0@10115658 was the one who helped you and I gave a medal

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0what is the second equation?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0you might want to use the "draw"

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0do you want me to help you to finish this or not?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry i was in the Bathroom

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0ok fine leave this open so someone else will was just about to leave

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0what is the second equation? and do you know how to get rid of the fraction?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ive been stuck on this all day

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0single out the x variable?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0work with me to get you out the rut

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0again what is the second equation?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1432968481833:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0now can you get rid of the fraction?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0do you remember how you would do something like dw:1432968632299:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0you can let me know when you are back if you want me to continue

Jack1
 one year ago
Best ResponseYou've already chosen the best response.1sorry im coming into this late give me a sec...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its fine ill take all the help

Jack1
 one year ago
Best ResponseYou've already chosen the best response.1\(\large x^2 + y^2 = 25\) so whoever it was in the q isolated x^2 from the 1st equation... yeah? so would look like \(\large x^2 + y^2 = 25\) \(\large x^2 = 25  y^2\) I'm proly goin whay too slow, but you with me so far?

Jack1
 one year ago
Best ResponseYou've already chosen the best response.1cool, so next they subbed this : \(\large \color{red} {x^2 = 25  y^2}\) into the 2nd equation: \(\huge \frac{x^2}{16}  \frac{y^2}9 = 1\) so would look something like this: \(\huge \frac{x^2}{16}  \frac{y^2}9 = 1\) \(\huge \frac{\color{red} {25  y^2}}{16}  \frac{y^2}9 = 1\) so u still with me man, any q's so far?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i wrote down all the steps for it

Jack1
 one year ago
Best ResponseYou've already chosen the best response.1cool man... so that's the resulting equation... u can solve it if u want, but the above's pretty much all they're lookin for in the q

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oksy thanks so much dude!
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