To solve the system of equations below, Zach isolated x2 in the first equation and then substituted it into the second equation. What was the resulting equation?

- anonymous

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- schrodinger

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- anonymous

http://media.apexlearning.com/Images/201011/29/c0be4b3b-9dcc-45a7-8483-d14f395ca1fc.gif

- triciaal

the same response you had earlier

- anonymous

none answered it

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## More answers

- triciaal

you have the expression for x^2 from the first equation. go ahead and use this expression in the second equation every time you see x^2 then solve the equation with the one variable

- triciaal

I just checked

- triciaal

don't be ungrateful!!! whenever you need more help just let the person know you need a bit more

- triciaal

@10115658 was the one who helped you and I gave a medal

- triciaal

what is the second equation?

- triciaal

you might want to use the "draw"

- triciaal

do you want me to help you to finish this or not?

- anonymous

sorry i was in the Bathroom

- triciaal

ok fine leave this open so someone else will
was just about to leave

- triciaal

what is the second equation?
and do you know how to get rid of the fraction?

- anonymous

ive been stuck on this all day

- anonymous

single out the x variable?

- triciaal

work with me to get you out the rut

- triciaal

again what is the second equation?

- triciaal

|dw:1432968481833:dw|

- anonymous

x^2/16-y^2/9=1

- anonymous

yes

- triciaal

now can you get rid of the fraction?

- triciaal

do you remember how you would do something like
|dw:1432968632299:dw|

- triciaal

you can let me know when you are back if you want me to continue

- anonymous

im writing it out

- anonymous

on paper

- anonymous

-2/15?

- anonymous

GCF

- Jack1

sorry im coming into this late give me a sec...

- anonymous

its fine ill take all the help

- Jack1

\(\large x^2 + y^2 = 25\)
so whoever it was in the q isolated x^2 from the 1st equation... yeah?
so would look like
\(\large x^2 + y^2 = 25\)
\(\large x^2 = 25 - y^2\)
I'm proly goin whay too slow, but you with me so far?

- anonymous

ya

- Jack1

cool,
so next they subbed this :
\(\large \color{red} {x^2 = 25 - y^2}\)
into the 2nd equation:
\(\huge \frac{x^2}{16} - \frac{y^2}9 = 1\)
so would look something like this:
\(\huge \frac{x^2}{16} - \frac{y^2}9 = 1\)
\(\huge \frac{\color{red} {25 - y^2}}{16} - \frac{y^2}9 = 1\)
so u still with me man, any q's so far?

- anonymous

i got it!

- anonymous

i wrote down all the steps for it

- Jack1

cool man... so that's the resulting equation... u can solve it if u want, but the above's pretty much all they're lookin for in the q

- anonymous

oksy thanks so much dude!

- Jack1

no worries man ;)

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