ayyookyndall
  • ayyookyndall
Help!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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nikato
  • nikato
area of pareelogram = base x height
ayyookyndall
  • ayyookyndall
So: 34 x 35?
nikato
  • nikato
|dw:1432964459874:dw|

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More answers

nikato
  • nikato
yes. 34x35
ayyookyndall
  • ayyookyndall
That is 1190
nikato
  • nikato
yup
ayyookyndall
  • ayyookyndall
Thats it?
anonymous
  • anonymous
do u have this nikato
nikato
  • nikato
that's it! and @ro561man what do you mean?
anonymous
  • anonymous
nvr mind you already solved it
nikato
  • nikato
|dw:1432964653201:dw|
anonymous
  • anonymous
i think you just double 30
anonymous
  • anonymous
which would get you 60
anonymous
  • anonymous
yup that look right srry i almost got u wrong
ayyookyndall
  • ayyookyndall
That equals 188.4 though....
anonymous
  • anonymous
is that not any of ur choices
ayyookyndall
  • ayyookyndall
So @ro561man is correct?.. @nikato Thats a choice and that seems like the correct answer.
anonymous
  • anonymous
yeah
anonymous
  • anonymous
i gtg gn well morning but im just now going to bed lol
ayyookyndall
  • ayyookyndall
@nikato
anonymous
  • anonymous
i dont think i should help lol im srry my brain is hurting i think you have to solve the square then solve the circle and add up what u get tho gn
ayyookyndall
  • ayyookyndall
Goodnight @ro561man
anonymous
  • anonymous
thnx
anonymous
  • anonymous
@nikato please check this i gtg
triciaal
  • triciaal
for the circumference it says in terms of pi so it would be 60 pi
ayyookyndall
  • ayyookyndall
We got that @triciaal I am just looking for an equation for the volume of the oblique cone shown. Can you help me with that?
triciaal
  • triciaal
sorry but I did not get to that yet
triciaal
  • triciaal
volume of a cone is 1/3*pi*r^2*h do you already have that?
ayyookyndall
  • ayyookyndall
The answer is 3461.85, correct? @triciaal
triciaal
  • triciaal
I was looking at the question
triciaal
  • triciaal
|dw:1432969715098:dw|
triciaal
  • triciaal
yes
ayyookyndall
  • ayyookyndall
Okay, thank you so much! I am going to close this question now. ;-)
triciaal
  • triciaal
you are welcome

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