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anonymous
 one year ago
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anonymous
 one year ago
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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{d}{dt}(\vec V.\frac{d \vec V}{dt} \times \frac{d^2 \vec V}{dt^2})\]\[\vec V . \frac{d \vec V}{dt} \times \frac{d^3 \vec V}{dt^3}+\vec V.\frac{d^2 \vec V}{dt^2} \times \frac{d^2 \vec V}{dt^2}+\frac{d \vec V}{dt}.\frac{d \vec V}{dt} \times \frac{d^2 \vec V}{dt^2}\] This becomes\[\vec V . \frac{d \vec V}{dt} \times \frac{d^3 \vec V}{dt^3}+0+0=\vec V . \frac{d \vec V}{dt} \times \frac{d^3 \vec V}{dt^3}\] Why are the last 2 terms zero??

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0oh wow what subject is this?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0really? I wasn't given that type of problem when I took the course. maybe I got lucky :S

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Maybe u can help?Take a look anyway pls, I'm only preparing for college, so there's no hurry :)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0besides there could be dot product and cross product O_O!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i do have an idea about the second one.. both the terms are same in cross product so the angle between them is 0 ... so the result will be zero

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I was thinking the same but then the 3rd term makes no sense

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it does.. look closely its box product and two vectors are same

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh so it's like one those methods where u rearrange triple product and it remains the same??In that way u can arrange the same vectors to come into the cross product so that it becomes 0

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1second last term you are cross same thing  theta =0 last term you are dotting something with its cross product => 0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I thought that stuff was not important at all, I just didn't want to learn the order you have to know when rearranging but now I've got it down.... also dot product of a vector with it's cross product with another vector is 0 ?? let's see, cross product of A and B will be perpendicular to both A and B so the dot product of this new vector with A will be....theta will be 90 cos90=0... I understand it all now
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