kanwal32
  • kanwal32
A bullet of mass m and charge q is fired towards a solid uniformly charged sphere of radius R and total charge +q. If it strikes the surface of sphere with speed u, find the minimum value of u so that it can penetrates through the sphere
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
kanwal32
  • kanwal32
|dw:1432973996650:dw|
kanwal32
  • kanwal32
@IrishBoy123
kanwal32
  • kanwal32
help

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

kanwal32
  • kanwal32
1mv^2/2=Kq^2/r
kanwal32
  • kanwal32
|dw:1432974143504:dw|
kanwal32
  • kanwal32
@tHe_FiZiCx99
kanwal32
  • kanwal32
@IrishBoy123 hlp
kanwal32
  • kanwal32
@IrishBoy123 @Compassionate
kanwal32
  • kanwal32
@paperbacon @ParthKohli
IrishBoy123
  • IrishBoy123
it's a sphere of uniform charge so there is a field inside it: E = k q r / R^3 where r is measured out from centre of sphere see here: http://hyperphysics.phy-astr.gsu.edu/hbase/electric/elesph.html the field will repel the bullet until/unless bullet reaches centre of sphere, then it will push the built out in the other direction. the bullet needs sifficient kinetic energy in order "work" it was to the centre of the sphere. yes? does that sound right?
kanwal32
  • kanwal32
can u give the soln
kanwal32
  • kanwal32
pls
IrishBoy123
  • IrishBoy123
W = F.x F = E.q \[W = \int\limits_{R}^{0} \frac{k \ q^2 \ r}{R^3} \ dr = - \frac{k \ q^2 }{R^3} \frac{R^2}{2} = - \frac{k \ q^2 }{2R}\] minus 'cos that is the energy the bullet will lose so -kq^2/2R + 1/2 m u^2 = 0 \[u = \sqrt{\frac{k q^2}{mR}}\] pls pls pls check algebra as i am actually trying to make breakfast here!! but that is "how" you could do it. key is that hyperphysics thing i linked
kanwal32
  • kanwal32
thnx same i was thinking
IrishBoy123
  • IrishBoy123
of course this assumes the charge sphere is made of jelly :p
kanwal32
  • kanwal32
yes no resistance
IrishBoy123
  • IrishBoy123
glad you agree. i clarification: "minus 'cos that is the **KE** energy the bullet will lose [ but the **PE** the bullet will gain**]" or looked at another way, that is the "work" the bullet will have to do, and the KE it will lose, in order to get to the centre of the sphere.

Looking for something else?

Not the answer you are looking for? Search for more explanations.