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vera_ewing
 one year ago
If the equilibrium constant is much less than 1, what can you conclude about the concentrations of the reactants and products?
A. Products are in the numerator of the equilibrium expression, so the concentration of the products is high.
B. Reactants are in the numerator of the equilibrium expression, so the concentration of the products is high.
C. Reactants are in the numerator of the equilibrium expression, so the concentration of the reactants is high.
D. Products are in the numerator of the equilibrium expression, so the concentration of the reactants is high.
vera_ewing
 one year ago
If the equilibrium constant is much less than 1, what can you conclude about the concentrations of the reactants and products? A. Products are in the numerator of the equilibrium expression, so the concentration of the products is high. B. Reactants are in the numerator of the equilibrium expression, so the concentration of the products is high. C. Reactants are in the numerator of the equilibrium expression, so the concentration of the reactants is high. D. Products are in the numerator of the equilibrium expression, so the concentration of the reactants is high.

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sweetburger
 one year ago
Best ResponseYou've already chosen the best response.1aA+bB>cC+dD and Eq= ([C]^c[D]^d)/([B]^b[A]^a) so if the equillibrium constant is much less than 1 we know that there is far more reactants than products at equilibrium. It is neither A or B in this case. It cannot be B. because Reactants are in the denominator, and it cannot be A. because if the concentrations of the products were high the Equilibrium constant would be much greater than 1.

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.1Well your fishing for answers now :P, but no its not actually C. I don't know how much you really want to learn this, but I did write in the post above the the Products were in the numerator and C. states that the reactants are in the numerator.

sweetburger
 one year ago
Best ResponseYou've already chosen the best response.1Well just confirming from what I said earlier this website clearly shows that the products are in the numerator and the reactants in the denominator. This is a verified source.

vera_ewing
 one year ago
Best ResponseYou've already chosen the best response.0I think there is a mistake with these practice problems. I'll let my teacher know.
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