vera_ewing
  • vera_ewing
If the equilibrium constant is much less than 1, what can you conclude about the concentrations of the reactants and products? A. Products are in the numerator of the equilibrium expression, so the concentration of the products is high. B. Reactants are in the numerator of the equilibrium expression, so the concentration of the products is high. C. Reactants are in the numerator of the equilibrium expression, so the concentration of the reactants is high. D. Products are in the numerator of the equilibrium expression, so the concentration of the reactants is high.
Chemistry
schrodinger
  • schrodinger
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vera_ewing
  • vera_ewing
@Somy A or B?
sweetburger
  • sweetburger
aA+bB-->cC+dD and Eq= ([C]^c[D]^d)/([B]^b[A]^a) so if the equillibrium constant is much less than 1 we know that there is far more reactants than products at equilibrium. It is neither A or B in this case. It cannot be B. because Reactants are in the denominator, and it cannot be A. because if the concentrations of the products were high the Equilibrium constant would be much greater than 1.
vera_ewing
  • vera_ewing
Ohh so it's C?

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sweetburger
  • sweetburger
Well your fishing for answers now :P, but no its not actually C. I don't know how much you really want to learn this, but I did write in the post above the the Products were in the numerator and C. states that the reactants are in the numerator.
vera_ewing
  • vera_ewing
It was C /:
sweetburger
  • sweetburger
http://chemwiki.ucdavis.edu/Physical_Chemistry/Equilibria/Chemical_Equilibria/The_Equilibrium_Constant
sweetburger
  • sweetburger
Well just confirming from what I said earlier this website clearly shows that the products are in the numerator and the reactants in the denominator. This is a verified source.
vera_ewing
  • vera_ewing
I think there is a mistake with these practice problems. I'll let my teacher know.

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