I have 3 math questions i need help with please help me

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I have 3 math questions i need help with please help me

Mathematics
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5. If A(5, 5), B(3, 3), C(6, 8), and D(-3, 4), what is the length of AB? Round to the nearest tenth. (Points : 1) Question 6. 6. If A(5, 5), B(3, 3), C(6, 8), and D(-3, 4), what is the length of BC? Round to the nearest tenth. (Points : 1) Question 7. 7. If A(5, 5), B(3, 3), C(6, 8), and D(-3, 4), what is the length of CD? Round to the nearest tenth. (Points : 1)
do you got to ca

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Distance formula is \[d=\sqrt{(x _{2}-x _{1})^2+(y_{2}-y_{1})^2}\]
Just take the x's and y's of the two points and plug them in to find the distance between them :)
i really don't understand how to do this ive been on this question for the pass hour and i cant get it wrong
Just plug the values into the formula I provided. The equation with the larger x will be the x2 and y2 equation.
Would you like me to walk you through the first one?
Please
So we're trying to find the distance between A and B. A is (5,5) and B is (3,3). Since 5 is greater than 3, A is going to be our x2, y2 equation and B is our x1, x2 equation. Now we just plug them into the formula. \[d=\sqrt{(5-3)^2+(5-3)^2}\] Solve the parentheses \[d=\sqrt{(2)^2+(2)^2}\] Find the square of it\[d=\sqrt{4+4}\]Add\[d=\sqrt{8}\] Since we're rounding to the nearest hundredth, that means that we're just gonna plug this into a calculator to find the result.
the first one is 6 right?
I just did the first one.
I did #5, as that is the first one on the list
oh okay lol i think i can do the last two or at least try
How about this? You set up the second one and if I need to, I'll correct you and help you through #6. After that, you do #7 on your own
okay i'll try
I don't know what to do after the first part i got 20. I don't think its right im sorry im like really bad at math
What did your initial setup look like?
I mean what did you fill in for \[d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }\]
yeah with 5 and 8
and i got 20
Did it look something like this?\[d=\sqrt{(6-3)^2+(8-3)^2 }\]
yeah but not those numbers
Why not those numbers? We're doing #6 are we not?
28?
28? What about 28?
The answer to the first step?
\[d=\sqrt{(3)^2+(5)^2}\]
I got 28 again
\[d=\sqrt{(3*3)+(5*5)}\]
28 is it 28?
How in the world are you getting 28? And are you not paying attention to my posts? I'm helping you through it. I am seriously confused as to how you're getting 28
I dont know im using my calculator but i don't understand this thanks for helping though i appreciate it
Right now we have this\[d=\sqrt{(3*3)+(5*5)}\] Can you solve the parentheses?

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