I have 3 math questions i need help with please help me

- anonymous

I have 3 math questions i need help with please help me

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- anonymous

5. If A(5, 5), B(3, 3), C(6, 8), and D(-3, 4), what is the length of AB? Round to the nearest tenth. (Points : 1)
Question 6. 6. If A(5, 5), B(3, 3), C(6, 8), and D(-3, 4), what is the length of BC? Round to the nearest tenth. (Points : 1)
Question 7. 7. If A(5, 5), B(3, 3), C(6, 8), and D(-3, 4), what is the length of CD? Round to the nearest tenth. (Points : 1)

- anonymous

@pooja195

- anonymous

do you got to ca

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## More answers

- anonymous

Distance formula is \[d=\sqrt{(x _{2}-x _{1})^2+(y_{2}-y_{1})^2}\]

- anonymous

Just take the x's and y's of the two points and plug them in to find the distance between them :)

- anonymous

i really don't understand how to do this ive been on this question for the pass hour and i cant get it wrong

- anonymous

Just plug the values into the formula I provided. The equation with the larger x will be the x2 and y2 equation.

- anonymous

Would you like me to walk you through the first one?

- anonymous

Please

- anonymous

So we're trying to find the distance between A and B. A is (5,5) and B is (3,3). Since 5 is greater than 3, A is going to be our x2, y2 equation and B is our x1, x2 equation. Now we just plug them into the formula. \[d=\sqrt{(5-3)^2+(5-3)^2}\] Solve the parentheses \[d=\sqrt{(2)^2+(2)^2}\] Find the square of it\[d=\sqrt{4+4}\]Add\[d=\sqrt{8}\] Since we're rounding to the nearest hundredth, that means that we're just gonna plug this into a calculator to find the result.

- anonymous

the first one is 6 right?

- anonymous

I just did the first one.

- anonymous

I did #5, as that is the first one on the list

- anonymous

oh okay lol i think i can do the last two or at least try

- anonymous

How about this? You set up the second one and if I need to, I'll correct you and help you through #6. After that, you do #7 on your own

- anonymous

okay i'll try

- anonymous

I don't know what to do after the first part i got 20. I don't think its right im sorry im like really bad at math

- anonymous

What did your initial setup look like?

- anonymous

I mean what did you fill in for \[d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }\]

- anonymous

yeah with 5 and 8

- anonymous

and i got 20

- anonymous

Did it look something like this?\[d=\sqrt{(6-3)^2+(8-3)^2 }\]

- anonymous

yeah but not those numbers

- anonymous

Why not those numbers? We're doing #6 are we not?

- anonymous

28?

- anonymous

28? What about 28?

- anonymous

The answer to the first step?

- anonymous

\[d=\sqrt{(3)^2+(5)^2}\]

- anonymous

I got 28 again

- anonymous

\[d=\sqrt{(3*3)+(5*5)}\]

- anonymous

28 is it 28?

- anonymous

How in the world are you getting 28? And are you not paying attention to my posts? I'm helping you through it. I am seriously confused as to how you're getting 28

- anonymous

I dont know im using my calculator but i don't understand this thanks for helping though i appreciate it

- anonymous

Right now we have this\[d=\sqrt{(3*3)+(5*5)}\] Can you solve the parentheses?

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