algebra!

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algebra!

Mathematics
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√x+6−4=x √x+2=x Step 1: Add -2 to both sides. √x+2+−2=x+−2 √x=x−2 Step 2: Solve Square Root. √x=x−2 x=(x−2)2(Square both sides) x=x2−4x+4 x−(x2−4x+4)=x2−4x+4−(x2−4x+4)(Subtract x^2-4x+4 from both sides) −x2+5x−4=0 (−x+1)(x−4)=0(Factor left side of equation) −x+1=0 or x−4=0(Set factors equal to 0) x=1 or x=4 Check answers. (Plug them in to make sure they work.) x=1(Doesn't work in original equation) x=4(Works in original equation)
Yes
Its saying to solve for X right?

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Other answers:

huh ? :/
Let's solve your equation step-by-step. √x+6−4=x Step 1: Add 4 to both sides. √x+6−4+4=x+4 √x+6=x+4 Step 2: Solve Square Root. √x+6=x+4 x+6=(x+4)2(Square both sides) x+6=x2+8x+16 x+6−(x2+8x+16)=x2+8x+16−(x2+8x+16)(Subtract x^2+8x+16 from both sides) −x2−7x−10=0 (−x−2)(x+5)=0(Factor left side of equation) −x−2=0 or x+5=0(Set factors equal to 0) x=−2 or x=−5 Check answers. (Plug them in to make sure they work.) x=−2(Works in original equation) x=−5(Doesn't work in original equation) Answer: x=−2
You get this
Its still one solution i dont know why you have an X and Y value
yep :) do you get it?
hahah thanks ok! :) but always double check your work :)

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