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emmiepie

  • one year ago

A 98-N sack of grain is hoisted to a storage room 50 m above the ground floor of a grain elevator a. How much work was required? b. What is the potential energy of the sack of grain at this height? c. The rope being used to lift the sack of grain breaks just as the sack reaches the storage room. What kinetic energy does the sack have just before it strikes the ground floor?

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  1. shamim
    • one year ago
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    a. W=F*h

  2. shamim
    • one year ago
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    Here W=work F=force h=height

  3. shamim
    • one year ago
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    W=?

  4. shamim
    • one year ago
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    b. P.E=w

  5. emmiepie
    • one year ago
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    This isn't helping me.

  6. shamim
    • one year ago
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    Ok. I m trying to help u!!

  7. shamim
    • one year ago
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    U know Work=force*displacement Right?

  8. shamim
    • one year ago
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    Weight of sack is=98N Right?

  9. shamim
    • one year ago
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    So u need to spply a force of 98N to lift the sack of grain.

  10. shamim
    • one year ago
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    Now displacement =?

  11. shamim
    • one year ago
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    Here displacement = height=50m

  12. shamim
    • one year ago
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    So W=?

  13. shamim
    • one year ago
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    Response plz!!

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