wade123
  • wade123
HELP PLEASE WITH AN ALGEBRA QUESTION
Mathematics
jamiebookeater
  • jamiebookeater
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

wade123
  • wade123
@Loser66 PLEASE HELP!!
Loser66
  • Loser66
n is the degree of it, right?
wade123
  • wade123
yes

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Loser66
  • Loser66
hence, it is a cubic, right?
wade123
  • wade123
right!
Loser66
  • Loser66
what are they? the zeros??
Loser66
  • Loser66
I don't get, 3 and 4 and 5i?? you meant you have 3 zeros?
Loser66
  • Loser66
Can you scan and post the original problem? don't type
wade123
  • wade123
i dont have time
Loser66
  • Loser66
ok, it is (58/9) (x^2 +5)(x -4) if it is not that, I don't know how to solve it.
Loser66
  • Loser66
you open parentheses to get the expand form
Michele_Laino
  • Michele_Laino
please try this polynomial: \[\Large f\left( z \right) = k\left( {z - 3} \right)\left( {z - 4} \right)\left( {z - 5i} \right)\]
Michele_Laino
  • Michele_Laino
you have to determine k, such that the subsequent condition holds: \[\Large f\left( { - 2} \right) = 116\] namely your condition
Michele_Laino
  • Michele_Laino
Loser66
  • Loser66
he has only 2 roots, not 3, 3 is the degree of the polynomial @Michele_Laino
Michele_Laino
  • Michele_Laino
ok!
Loser66
  • Loser66
One more thing: Although -5i is not stated out, but when we have 5i is a root, then, so as -5i, right?
Michele_Laino
  • Michele_Laino
yes!
Loser66
  • Loser66
ok

Looking for something else?

Not the answer you are looking for? Search for more explanations.