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anonymous
 one year ago
The red light from a HeNe (heliumneon) laser has a wavelength of 633 nm. What is the frequency of the light?
A. 4.7 × 10^14 Hz
B. 4.7 × 10^5 Hz
C. 190 Hz
D. 1.9 × 10^11 Hz
anonymous
 one year ago
The red light from a HeNe (heliumneon) laser has a wavelength of 633 nm. What is the frequency of the light? A. 4.7 × 10^14 Hz B. 4.7 × 10^5 Hz C. 190 Hz D. 1.9 × 10^11 Hz

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Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1it is simple, since we have to apply this formula: \[\Large \lambda \nu = c\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay!! what do we plug in? :/

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1here is the computation: \[\Large \nu = \frac{c}{\lambda } = \frac{{3 \times {{10}^{10}}}}{{6.33 \times {{10}^{  7}}}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay!! and so we get 4.739336493E16 ?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1where I have used these values: c=3*10^10 cm/sec \lambda=633*10^9 meters = 6.33*10^7 meters=6.33*1^5 cm

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and so our solution is choice A?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1please wait, I have made an error, here is the right computation: \[\Large \nu = \frac{c}{\lambda } = \frac{{3 \times {{10}^{10}}}}{{6.33 \times {{10}^{  5}}}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohh okay!! so we get 4.739336493E14? so that is choice A still? :P

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1that's right! It is option A

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1since the wave length is: 633 nm= 6.33*10^5 cm
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