## A community for students. Sign up today

Here's the question you clicked on:

## anonymous one year ago The red light from a He-Ne (helium-neon) laser has a wavelength of 633 nm. What is the frequency of the light? A. 4.7 × 10^14 Hz B. 4.7 × 10^5 Hz C. 190 Hz D. 1.9 × 10^11 Hz

• This Question is Closed
1. Michele_Laino

it is simple, since we have to apply this formula: $\Large \lambda \nu = c$

2. anonymous

okay!! what do we plug in? :/

3. Michele_Laino

here is the computation: $\Large \nu = \frac{c}{\lambda } = \frac{{3 \times {{10}^{10}}}}{{6.33 \times {{10}^{ - 7}}}}$

4. anonymous

okay!! and so we get 4.739336493E16 ?

5. Michele_Laino

where I have used these values: c=3*10^10 cm/sec \lambda=633*10^-9 meters = 6.33*10^-7 meters=6.33*1^-5 cm

6. anonymous

ahh okie!

7. anonymous

and so our solution is choice A?

8. Michele_Laino

please wait, I have made an error, here is the right computation: $\Large \nu = \frac{c}{\lambda } = \frac{{3 \times {{10}^{10}}}}{{6.33 \times {{10}^{ - 5}}}}$

9. anonymous

ohh okay!! so we get 4.739336493E14? so that is choice A still? :P

10. Michele_Laino

ok!

11. Michele_Laino

that's right! It is option A

12. anonymous

yay!! thank you!!

13. Michele_Laino

since the wave length is: 633 nm= 6.33*10^-5 cm

14. anonymous

:)

15. Michele_Laino

thank you!! :)

#### Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy