anonymous
  • anonymous
The red light from a He-Ne (helium-neon) laser has a wavelength of 633 nm. What is the frequency of the light? A. 4.7 × 10^14 Hz B. 4.7 × 10^5 Hz C. 190 Hz D. 1.9 × 10^11 Hz
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Michele_Laino
  • Michele_Laino
it is simple, since we have to apply this formula: \[\Large \lambda \nu = c\]
anonymous
  • anonymous
okay!! what do we plug in? :/
Michele_Laino
  • Michele_Laino
here is the computation: \[\Large \nu = \frac{c}{\lambda } = \frac{{3 \times {{10}^{10}}}}{{6.33 \times {{10}^{ - 7}}}}\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
okay!! and so we get 4.739336493E16 ?
Michele_Laino
  • Michele_Laino
where I have used these values: c=3*10^10 cm/sec \lambda=633*10^-9 meters = 6.33*10^-7 meters=6.33*1^-5 cm
anonymous
  • anonymous
ahh okie!
anonymous
  • anonymous
and so our solution is choice A?
Michele_Laino
  • Michele_Laino
please wait, I have made an error, here is the right computation: \[\Large \nu = \frac{c}{\lambda } = \frac{{3 \times {{10}^{10}}}}{{6.33 \times {{10}^{ - 5}}}}\]
anonymous
  • anonymous
ohh okay!! so we get 4.739336493E14? so that is choice A still? :P
Michele_Laino
  • Michele_Laino
ok!
Michele_Laino
  • Michele_Laino
that's right! It is option A
anonymous
  • anonymous
yay!! thank you!!
Michele_Laino
  • Michele_Laino
since the wave length is: 633 nm= 6.33*10^-5 cm
anonymous
  • anonymous
:)
Michele_Laino
  • Michele_Laino
thank you!! :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.