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anonymous

  • one year ago

The red light from a He-Ne (helium-neon) laser has a wavelength of 633 nm. What is the frequency of the light? A. 4.7 × 10^14 Hz B. 4.7 × 10^5 Hz C. 190 Hz D. 1.9 × 10^11 Hz

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  1. Michele_Laino
    • one year ago
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    it is simple, since we have to apply this formula: \[\Large \lambda \nu = c\]

  2. anonymous
    • one year ago
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    okay!! what do we plug in? :/

  3. Michele_Laino
    • one year ago
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    here is the computation: \[\Large \nu = \frac{c}{\lambda } = \frac{{3 \times {{10}^{10}}}}{{6.33 \times {{10}^{ - 7}}}}\]

  4. anonymous
    • one year ago
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    okay!! and so we get 4.739336493E16 ?

  5. Michele_Laino
    • one year ago
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    where I have used these values: c=3*10^10 cm/sec \lambda=633*10^-9 meters = 6.33*10^-7 meters=6.33*1^-5 cm

  6. anonymous
    • one year ago
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    ahh okie!

  7. anonymous
    • one year ago
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    and so our solution is choice A?

  8. Michele_Laino
    • one year ago
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    please wait, I have made an error, here is the right computation: \[\Large \nu = \frac{c}{\lambda } = \frac{{3 \times {{10}^{10}}}}{{6.33 \times {{10}^{ - 5}}}}\]

  9. anonymous
    • one year ago
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    ohh okay!! so we get 4.739336493E14? so that is choice A still? :P

  10. Michele_Laino
    • one year ago
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    ok!

  11. Michele_Laino
    • one year ago
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    that's right! It is option A

  12. anonymous
    • one year ago
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    yay!! thank you!!

  13. Michele_Laino
    • one year ago
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    since the wave length is: 633 nm= 6.33*10^-5 cm

  14. anonymous
    • one year ago
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    :)

  15. Michele_Laino
    • one year ago
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    thank you!! :)

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