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grimsnightmare

  • one year ago

How do you correct samples of gases to standard temperature?

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  1. grimsnightmare
    • one year ago
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    I have; 622 cm^3 at 15.0 C and another 55.6 dm^3 at 110 K

  2. Teddyiswatshecallsme
    • one year ago
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    V2 = 589.6cm³ for #1 & 138.0 dm³ for #2

  3. aaronq
    • one year ago
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    Use the formula: \(\large \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\) For example, for the first set of conditions: \(V_1\)=622 cm^3 \(T_1\)= 15.0 C + 273 = 288 K \(V_2\)= unknown \(T_2\)= 273 K \(\large \dfrac{622~ cm ^3}{288 ~K}=\dfrac{V_2}{273~K}\rightarrow V_2=\dfrac{273~K*622~ cm ^3}{288 ~K}=589.6~cm^3 \)

  4. grimsnightmare
    • one year ago
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    Thank you so much for explaining that! Sorry I didn't respond earlier I was working on something else.

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