anonymous
  • anonymous
find the axis of symmetry for y=3x^2+5x-7 a)x=5 b)x=-5/3 c)x=-7 d)x=-5/6
Mathematics
katieb
  • katieb
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Loser66
  • Loser66
What is the x coordinate of the vertex?
anonymous
  • anonymous
it dosnt give me one
Loser66
  • Loser66
sure, you have to find it out

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Loser66
  • Loser66
by formula x = -b/2a
anonymous
  • anonymous
huh im so sorry im wakeful at this lol
anonymous
  • anonymous
awful*
anonymous
  • anonymous
\[y =3x^2+5x -7\] do you know how to do the completing the square? Look at the attachment, it briefly shows you how to do it. So If I complete the square given in the question then it will be \[y = 3(x + \frac{ 5 }{ 3 })^2-\frac{ 25 }{ 9 } - 7\] the x you see in this equation has to be to which if you add 5/3 will give you 0 Sp bring 5/3 to the other side \[x = -\frac{ 5 }{ 3 }\] back to the original equation so when x is -5/3 your y will be: \[y = -\frac{ 88 }{ 9 }\] the x is the line of symmetry |dw:1433012607952:dw|
anonymous
  • anonymous
I didn't check the discriminant so Idk if the parabola is having any x-intercept btw what @Loser66 said is correct I simply gave you the explanation for the formula
Loser66
  • Loser66
@nopen x = -b/2a = - 5/6
anonymous
  • anonymous
Oops the 6
anonymous
  • anonymous
lol
Loser66
  • Loser66
hehehe.. you got it.

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