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anonymous

  • one year ago

find the axis of symmetry for y=3x^2+5x-7 a)x=5 b)x=-5/3 c)x=-7 d)x=-5/6

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  1. Loser66
    • one year ago
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    What is the x coordinate of the vertex?

  2. anonymous
    • one year ago
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    it dosnt give me one

  3. Loser66
    • one year ago
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    sure, you have to find it out

  4. Loser66
    • one year ago
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    by formula x = -b/2a

  5. anonymous
    • one year ago
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    huh im so sorry im wakeful at this lol

  6. anonymous
    • one year ago
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    awful*

  7. anonymous
    • one year ago
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    \[y =3x^2+5x -7\] do you know how to do the completing the square? Look at the attachment, it briefly shows you how to do it. So If I complete the square given in the question then it will be \[y = 3(x + \frac{ 5 }{ 3 })^2-\frac{ 25 }{ 9 } - 7\] the x you see in this equation has to be to which if you add 5/3 will give you 0 Sp bring 5/3 to the other side \[x = -\frac{ 5 }{ 3 }\] back to the original equation so when x is -5/3 your y will be: \[y = -\frac{ 88 }{ 9 }\] the x is the line of symmetry |dw:1433012607952:dw|

  8. anonymous
    • one year ago
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    I didn't check the discriminant so Idk if the parabola is having any x-intercept btw what @Loser66 said is correct I simply gave you the explanation for the formula

  9. Loser66
    • one year ago
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    @nopen x = -b/2a = - 5/6

  10. anonymous
    • one year ago
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    Oops the 6

  11. anonymous
    • one year ago
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    lol

  12. Loser66
    • one year ago
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    hehehe.. you got it.

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