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anonymous
 one year ago
A 6,600 kg train car moving at +2.0 m/s bumps into and locks together with one of mass 5,400 kg moving at 3.0 m/s. What is their final velocity?
A. 0.25 m/s
B. 1.0 m/s
C. +0.50 m/s
D. +2.5 m/s
anonymous
 one year ago
A 6,600 kg train car moving at +2.0 m/s bumps into and locks together with one of mass 5,400 kg moving at 3.0 m/s. What is their final velocity? A. 0.25 m/s B. 1.0 m/s C. +0.50 m/s D. +2.5 m/s

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Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2since the system composed by the two trains, is isolated along the direction of the motion, namely no external forces, along the direction of motion are acting on our trains, then we can write: \[\Large {M_1}{V_1} + {M_2}{V_2} = \left( {{M_1} + {M_2}} \right)V\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2V is the final velocity

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2namely: \[\Large V = \frac{{{M_1}{V_1} + {M_2}{V_2}}}{{{M_1} + {M_2}}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay! what do i plug in?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2here is the next step: \[\Large V = \frac{{{M_1}{V_1} + {M_2}{V_2}}}{{{M_1} + {M_2}}} = \frac{{\left( {6600 \times 2} \right) + \left\{ {5400 \times \left( {  3} \right)} \right\}}}{{6600 + 5400}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i cannot see the last part you wrote!! i just see (6600*2) + [5400  6600+5400 what was the rest of it?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2sorry, here is the formula: \[V = \frac{{{M_1}{V_1} + {M_2}{V_2}}}{{{M_1} + {M_2}}} = \frac{{\left( {6600 \times 2} \right) + \left\{ {5400 \times \left( {  3} \right)} \right\}}}{{6600 + 5400}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohh okay!! i see it now:) so we get 0.495 ?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2I got a different result

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh oops sorry i got 0.25 !! i entered something wrong earlier!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yay! so our solution is choice A?
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