anonymous
  • anonymous
someone help me understand this :(
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
anonymous
  • anonymous
tangent of any angle of a right angled triangle = height of that triangle/base of that triangle
anonymous
  • anonymous
for your diagram height = 27500 base = 5000

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anonymous
  • anonymous
yes i got that. i just dont understand the last step :( how did they get that answer?
anonymous
  • anonymous
im using that as an example for a question my test i just got so confused at the last part
anonymous
  • anonymous
on my**
johnweldon1993
  • johnweldon1993
That is where you take the inverse tangent function of that whole expression \[\large tan(x) = 5.5 \rightarrow x = tan^{-1}(5.5)\]
anonymous
  • anonymous
ohh okay. can i put the question from my test on here and ill walk through the steps and you tell me if im the right track or not?
johnweldon1993
  • johnweldon1993
It will work like that with all your trig functions If \(\large sin(x) = \text{something}\rightarrow x = \sin^{-1}(\text{something})\) If \(\large cos(x) = \text{something}\rightarrow x = \cos^{-1}(\text{something})\) If \(\large tan(x) = \text{something}\rightarrow x = \tan^{-1}(\text{something})\)
johnweldon1993
  • johnweldon1993
And yeah of course!
anonymous
  • anonymous
anonymous
  • anonymous
so i used sin for this one
johnweldon1993
  • johnweldon1993
Correct
anonymous
  • anonymous
and i got b
johnweldon1993
  • johnweldon1993
And you would be correct again :)
anonymous
  • anonymous
yes!! thank you so much :D
johnweldon1993
  • johnweldon1993
Not a problem! Good luck on the rest of your test :D

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