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anonymous

  • one year ago

someone help me understand this :(

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    tangent of any angle of a right angled triangle = height of that triangle/base of that triangle

  3. anonymous
    • one year ago
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    for your diagram height = 27500 base = 5000

  4. anonymous
    • one year ago
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    yes i got that. i just dont understand the last step :( how did they get that answer?

  5. anonymous
    • one year ago
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    im using that as an example for a question my test i just got so confused at the last part

  6. anonymous
    • one year ago
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    on my**

  7. johnweldon1993
    • one year ago
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    That is where you take the inverse tangent function of that whole expression \[\large tan(x) = 5.5 \rightarrow x = tan^{-1}(5.5)\]

  8. anonymous
    • one year ago
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    ohh okay. can i put the question from my test on here and ill walk through the steps and you tell me if im the right track or not?

  9. johnweldon1993
    • one year ago
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    It will work like that with all your trig functions If \(\large sin(x) = \text{something}\rightarrow x = \sin^{-1}(\text{something})\) If \(\large cos(x) = \text{something}\rightarrow x = \cos^{-1}(\text{something})\) If \(\large tan(x) = \text{something}\rightarrow x = \tan^{-1}(\text{something})\)

  10. johnweldon1993
    • one year ago
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    And yeah of course!

  11. anonymous
    • one year ago
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  12. anonymous
    • one year ago
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    so i used sin for this one

  13. johnweldon1993
    • one year ago
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    Correct

  14. anonymous
    • one year ago
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    and i got b

  15. johnweldon1993
    • one year ago
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    And you would be correct again :)

  16. anonymous
    • one year ago
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    yes!! thank you so much :D

  17. johnweldon1993
    • one year ago
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    Not a problem! Good luck on the rest of your test :D

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