## anonymous one year ago someone help me understand this :(

1. anonymous

2. anonymous

tangent of any angle of a right angled triangle = height of that triangle/base of that triangle

3. anonymous

for your diagram height = 27500 base = 5000

4. anonymous

yes i got that. i just dont understand the last step :( how did they get that answer?

5. anonymous

im using that as an example for a question my test i just got so confused at the last part

6. anonymous

on my**

7. johnweldon1993

That is where you take the inverse tangent function of that whole expression $\large tan(x) = 5.5 \rightarrow x = tan^{-1}(5.5)$

8. anonymous

ohh okay. can i put the question from my test on here and ill walk through the steps and you tell me if im the right track or not?

9. johnweldon1993

It will work like that with all your trig functions If $$\large sin(x) = \text{something}\rightarrow x = \sin^{-1}(\text{something})$$ If $$\large cos(x) = \text{something}\rightarrow x = \cos^{-1}(\text{something})$$ If $$\large tan(x) = \text{something}\rightarrow x = \tan^{-1}(\text{something})$$

10. johnweldon1993

And yeah of course!

11. anonymous

12. anonymous

so i used sin for this one

13. johnweldon1993

Correct

14. anonymous

and i got b

15. johnweldon1993

And you would be correct again :)

16. anonymous

yes!! thank you so much :D

17. johnweldon1993

Not a problem! Good luck on the rest of your test :D