## anonymous one year ago I am working on Analyzing Graphs of Quadratic Functions, the problem I am stuck on is f(x)=x^2/2+4x+4. I think the area I am messing up on is the squaring. Someone please putting this in the most simplest form. Algebra is my worst enemy.

1. anonymous

what exactly are you supposed to do?

2. anonymous

put it in the form f(x)=a(x-h)^2+k. find the vertex and graph it.

3. anonymous

is it $y=\frac{x^2}{2}+4x+4$?

4. anonymous

that's the original function. but I don't know how to work it out to because an order pair

5. anonymous

if you want to write in vertex form first factor out the $$\frac{1}{2}$$ from the first two terms and write $y=\frac{1}{2}(x^2+2x)+4$

6. anonymous

easiest way to find the vertex is to use $$-\frac{b}{2a}$$ for the first coordinate

7. anonymous

in your example it is $-\frac{4}{2\times \frac{1}{2}}=-4$

8. anonymous

i wrote something stupid $y=\frac{1}{2}(x^2+2x)+4$ if you factor out the $$\frac{1}{2}$$ you actually get $y=\frac{1}{2}(x^2+\color{red}8x)+4$

9. anonymous

thanks I got it now.