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anonymous

  • one year ago

n astronaut having mass 320 kg with equipment included is attempting an untethered space walk. The astronaut is initially at rest with respect to the nearby spacecraft, but discharges 30.0 g of nitrogen gas at 900.0 m/s from a portable propulsion unit. How fast is the astronaut moving after doing that? 0.36 m/s, 0.084 m/s , 27 m/s, or 84 m/s ?? :/

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  1. Michele_Laino
    • one year ago
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    here we have to apply the momentum conservation law

  2. anonymous
    • one year ago
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    ok!

  3. Michele_Laino
    • one year ago
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    so we can write this: \[P = 0.03 \times 900 = ...\] is the momentum of the gas discharged

  4. Michele_Laino
    • one year ago
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    oops..discharged gas

  5. Michele_Laino
    • one year ago
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    how much is P?

  6. anonymous
    • one year ago
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    errr 27?

  7. Michele_Laino
    • one year ago
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    ok!

  8. Michele_Laino
    • one year ago
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    the momentum gained by our astronaut is: \[P' = 320 \times V\] where V is his velocity

  9. Michele_Laino
    • one year ago
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    so we can write: \[27 = 320 \times V\] what is V?

  10. anonymous
    • one year ago
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    0.984375? so our solution is 0.084 m/s ?

  11. Michele_Laino
    • one year ago
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    \[V = \frac{{27}}{{320}} = {\text{0}}{\text{.084375}}\]

  12. Michele_Laino
    • one year ago
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    so V=0.084

  13. anonymous
    • one year ago
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    so is that our final solution? :O

  14. Michele_Laino
    • one year ago
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    yes!

  15. anonymous
    • one year ago
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    yay!! thank you!!

  16. Michele_Laino
    • one year ago
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    thank you!! :)

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