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I need help finding the domian and range for my graph for y=3(x-2)^2+1
this should help: http://www.purplemath.com/modules/fcns2.htm
@Nnesha could you help?
Hey Nnesha you helped me last time. I was wondering if you were familiar with this?
hey blue alright so are u allowed to graph it ?
yeah i have to graph it ( i did already) now i have to find the domain and range
domain of parabola is always going to be negative inf to positive inf|dw:1433021151849:dw|
|dw:1433021252047:dw|we don't know how longer its going to be so that's why domain is \[(- ∞, ∞)\]
now range is y value so |dw:1433021354845:dw| and range start from the vertex(y point) to positive ∞
the red line shows starting point of range
okay so the range is (positive inf,1)
starting point come first (start, end) so you don't know where its going to end so positive infinity
okay great I understand it now. one more question
okay yeah so i list those points?
parabola graph isn't crossing x-axis so no x-intercept is there any point where line cross y -axis ?
mhm yes there is a point where line cross y-axis if you r using desmos caluclator zoomout a little bit so you can see
okay one sec
my vertex for this problem is (2,1) my graph looks different from yours
oh yeah it's that's just an example (weird drawing ik ik ;D)
|dw:1433022493243:dw| find this blue point where line cross y-axis
|dw:1433022652761:dw| my graph literally shows like this because the points that i plotted were (1,4) and (3,4)
plotted point why did you plot points ?
http://prntscr.com/7b9y0p this is your graph do you see the point where line cross y-axis between 10 and 15 you need that point for y-intercept zoomout a little bit to see :-)
okay i see. im doing this by hand, so my graph only goes up to 5 lol. oops
Okay now lastly
ohhh okay so then you have to plug in 0 for x bec when line cross y-axis x value is 0
^^^ to find y-intercept b hand
the main question is for me to compare f(x)= a(x-h)^2 +k to f(x) x^2. i explained that they are basically the same its just that the h and k show us how left/right/up/down the curve has shifted. does that make sense?
y = x^2 is a basic form of quadratic function it shows the shape of parabola yes you are right the difference f(x)= a(x-h)^2 +k is a vertex form equation where h represent horizontal shift and k is for vertical shift where a is tell how how wider or Skinner the graph is going to be
in other words f(x)=x^2 is a parent function
Okay great YAY! I feel smart Thank you so much for helping me better understand, I wish I could repay you. Your not a qualified helper right? :-(
lol glad to hear that :-) yes i'm not QH and btw you didn't ask QH question :-)
Well thank you so much for taking the time out to help me, I really appreciate.
my pleasure :-) thanks!