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anonymous
 one year ago
Finding the domain and range
anonymous
 one year ago
Finding the domain and range

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I need help finding the domian and range for my graph for y=3(x2)^2+1

Z4K4R1Y4
 one year ago
Best ResponseYou've already chosen the best response.0this should help: http://www.purplemath.com/modules/fcns2.htm

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Nnesha could you help?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hey Nnesha you helped me last time. I was wondering if you were familiar with this?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2hey blue alright so are u allowed to graph it ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah i have to graph it ( i did already) now i have to find the domain and range

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2domain of parabola is always going to be negative inf to positive infdw:1433021151849:dw

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2dw:1433021252047:dwwe don't know how longer its going to be so that's why domain is \[( ∞, ∞)\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2now range is y value so dw:1433021354845:dw and range start from the vertex(y point) to positive ∞

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2the red line shows starting point of range

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so the range is (positive inf,1)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2starting point come first (start, end) so you don't know where its going to end so positive infinity

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay great I understand it now. one more question

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay yeah so i list those points?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2parabola graph isn't crossing xaxis so no xintercept is there any point where line cross y axis ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2mhm yes there is a point where line cross yaxis if you r using desmos caluclator zoomout a little bit so you can see

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0my vertex for this problem is (2,1) my graph looks different from yours

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2oh yeah it's that's just an example (weird drawing ik ik ;D)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2dw:1433022493243:dw find this blue point where line cross yaxis

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433022652761:dw my graph literally shows like this because the points that i plotted were (1,4) and (3,4)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2plotted point why did you plot points ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2http://prntscr.com/7b9y0p this is your graph do you see the point where line cross yaxis between 10 and 15 you need that point for yintercept zoomout a little bit to see :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay i see. im doing this by hand, so my graph only goes up to 5 lol. oops

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2ohhh okay so then you have to plug in 0 for x bec when line cross yaxis x value is 0

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2^^^ to find yintercept b hand

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the main question is for me to compare f(x)= a(xh)^2 +k to f(x) x^2. i explained that they are basically the same its just that the h and k show us how left/right/up/down the curve has shifted. does that make sense?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2y = x^2 is a basic form of quadratic function it shows the shape of parabola yes you are right the difference f(x)= a(xh)^2 +k is a vertex form equation where h represent horizontal shift and k is for vertical shift where a is tell how how wider or Skinner the graph is going to be

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2in other words f(x)=x^2 is a parent function

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay great YAY! I feel smart Thank you so much for helping me better understand, I wish I could repay you. Your not a qualified helper right? :(

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2lol glad to hear that :) yes i'm not QH and btw you didn't ask QH question :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well thank you so much for taking the time out to help me, I really appreciate.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2my pleasure :) thanks!
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