A man pushes a lawn mower with a force of 34 lb exerted at an angle of 30° to the ground. Find the horizontal and vertical components of the force. (Assume that the horizontal direction is positive and the vertical direction is negative.)

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A man pushes a lawn mower with a force of 34 lb exerted at an angle of 30° to the ground. Find the horizontal and vertical components of the force. (Assume that the horizontal direction is positive and the vertical direction is negative.)

Mathematics
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I got 17sq3i-17j
but it doesn't want it
Suggest you use geometry. You have a right triangle with the hypothenuse as your force of 32 lbs. The gravity/(vertical component) would be sin 30 degrees x 32. The horizontal component will be cos 30 degrees x 32. =( sqrt of 3) x 16.

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where did you get 32?
|dw:1433016210638:dw|
equation of force is F=fcos(theta)i+fsin(theta)j right?
That is the vector components yea, the i=<1,0> is the X direction, and the j=<0,1> is the y direction component
calculate each, Magnitude of F times cos(theta) for the x component, and magnitude of F times sin(theta) for the Y component
So then plugging numbers in we have: 34cos(30)i+34sin(30)j
simplifies to: 34(sq3/2)i+34(1/2)j
is that all correct?
\[F _{Tot}=F _{x}i+F _{y}j\]
yes, just calculate Fx and Fy, those are the legs of the triangle, the components of the force
um then the answer will be: \[17\sqrt{3}i+17j\]
Yeah? but they don't accept that answer
The vertical direction (UP) is said to be negative, so that component will be negative
oh sorry, right right. I wrote it wrong in here but wrote it correct into the answer box :P they don't like it
\[17\sqrt{3}i-17j\]
yeah, that is the Force written in component form. Not sure how you are supposed to enter the answer though
hrm..yeah because that should be right and the example is written that way too.
Previous questions in this homework have also rejected anything that has i or j in it, i'll just ask my prof monday :) thanks!!
yw

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