i need to use long division to solve: 4b^3+5b-3/2b-1

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i need to use long division to solve: 4b^3+5b-3/2b-1

Mathematics
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i lost that somehow... anyway sorry gotta go
long division 5 steps) \(\huge\color{green}{{1:}}\) Divide the first terms \(\huge\color{green}{{2:}}\) multiply(distribute) \(\huge\color{green}{{3:}}\) subtract all terms \(\huge\color{green}{{4:}}\) carry down \(\huge\color{green}{{5:}}\) repeat|dw:1433019343715:dw|
why do you add in the 0b^2?

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b^2 term isn't in the equation but we still have to write it in order highest to lowest degree 3,2,1,0
now divide first terms 4b^3/2b = ????
2b^2?
yep right :=) now multiply divisor by 2b^2|dw:1433019573973:dw| 2nd step distribute 2b^2 (2b-1 ) =?
then its gonna be 4b^3? which is going to cancel out right?..
yep right but 2b^2 (2b-1) = is not just equal to 4b^3 2b^2 times -1= -2b^2
|dw:1433019721662:dw|change signs 4b^3 and -4b^3 cancels out combine 0b^2 + 2b2
|dw:1433019788182:dw| now repeat the pattern divide first terms distribute by divisor change sign and then combine do ou want to try it ?
i think i get it now, i just got stuck where i had to add in the 0b^2, but its making alot more sense
so i did the rest of the problem.. is this right? 2b+b+3?
ohh alright yep number should be in order highest degree is 3 so 3 ,2,1,
why do i need it in the highest degree?
yes that's right 2b+b+3
highest degree is 3 in the equation 4b^3 <-- and this is first term so you have to start from highest degree to lowest
ohhh okay
yep good job!
thank you so much, i really appreciate it :D
my pleasure :-)
btw \(\huge\color{Green}{{\rm welcome}\rm~to~open~study!!!!}\) \(\Huge \color{gold}{\star^{ \star^{\star:)}}}\Huge \color{green}{\star^{ \star^{\star:)}}}\) \(\Huge \color{blue}{\star^{ \star^{\star:)}}}\Huge \color{red}{\star^{ \star^{\star:)}}}\) \(\Huge \color{orange}{\star^{ \star^{\star:)}}}\Huge \color{purple}{\star^{ \star^{\star:)}}}\)\(\rm\color{green}{o^\wedge\_^\wedge o}\)
haha thank you :D

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