## anonymous one year ago i need to use long division to solve: 4b^3+5b-3/2b-1

1. welshfella

i lost that somehow... anyway sorry gotta go

2. Nnesha

long division 5 steps) $$\huge\color{green}{{1:}}$$ Divide the first terms $$\huge\color{green}{{2:}}$$ multiply(distribute) $$\huge\color{green}{{3:}}$$ subtract all terms $$\huge\color{green}{{4:}}$$ carry down $$\huge\color{green}{{5:}}$$ repeat|dw:1433019343715:dw|

3. anonymous

why do you add in the 0b^2?

4. Nnesha

b^2 term isn't in the equation but we still have to write it in order highest to lowest degree 3,2,1,0

5. Nnesha

now divide first terms 4b^3/2b = ????

6. anonymous

2b^2?

7. Nnesha

yep right :=) now multiply divisor by 2b^2|dw:1433019573973:dw| 2nd step distribute 2b^2 (2b-1 ) =?

8. anonymous

then its gonna be 4b^3? which is going to cancel out right?..

9. Nnesha

yep right but 2b^2 (2b-1) = is not just equal to 4b^3 2b^2 times -1= -2b^2

10. Nnesha

|dw:1433019721662:dw|change signs 4b^3 and -4b^3 cancels out combine 0b^2 + 2b2

11. Nnesha

|dw:1433019788182:dw| now repeat the pattern divide first terms distribute by divisor change sign and then combine do ou want to try it ?

12. anonymous

i think i get it now, i just got stuck where i had to add in the 0b^2, but its making alot more sense

13. anonymous

so i did the rest of the problem.. is this right? 2b+b+3?

14. Nnesha

ohh alright yep number should be in order highest degree is 3 so 3 ,2,1,

15. anonymous

why do i need it in the highest degree?

16. Nnesha

yes that's right 2b+b+3

17. Nnesha

highest degree is 3 in the equation 4b^3 <-- and this is first term so you have to start from highest degree to lowest

18. anonymous

ohhh okay

19. Nnesha

yep good job!

20. anonymous

thank you so much, i really appreciate it :D

21. Nnesha

my pleasure :-)

22. Nnesha

btw $$\huge\color{Green}{{\rm welcome}\rm~to~open~study!!!!}$$ $$\Huge \color{gold}{\star^{ \star^{\star:)}}}\Huge \color{green}{\star^{ \star^{\star:)}}}$$ $$\Huge \color{blue}{\star^{ \star^{\star:)}}}\Huge \color{red}{\star^{ \star^{\star:)}}}$$ $$\Huge \color{orange}{\star^{ \star^{\star:)}}}\Huge \color{purple}{\star^{ \star^{\star:)}}}$$$$\rm\color{green}{o^\wedge\_^\wedge o}$$

23. anonymous

haha thank you :D