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anonymous
 one year ago
The period of a wave:
a. decreases with increasing frequency.
b. increases with increasing frequency.
c. increases with decreasing wavelength.
d. a and c only.
none of the above.
anonymous
 one year ago
The period of a wave: a. decreases with increasing frequency. b. increases with increasing frequency. c. increases with decreasing wavelength. d. a and c only. none of the above.

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Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[T = \frac{ 1 }{ f }\] what can we say about this formula (period)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That whichever number is below the 1 in the fraction is going to be the number itself?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Plug in some large and small numbers and see what happens and relate it to your options.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That whichever number is below the 1 in the fraction is going to be the number itself?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[f = \frac{ v }{ \lambda }\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1I don't know what you mean, can you elaborate, I don't see how it has to do with your question?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You asked what could I tell you about the first equation.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[T = \frac{ 1 }{ 10000000 }\] what happens if the frequency is that high, will the period decrease or increase?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Yes, now if we have \[T = \frac{ 1 }{ 0.000000001 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Then we have a frequency that goes higher.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Now if we plug \[\huge T = \frac{ 1 }{ \frac{ v }{ \lambda } } \implies \frac{ \lambda }{ v }\] what happens?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Im lost with everything passed T = 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0First time in physics ....

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know wavelength symbol.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Well lets say the speed is constant, \[T = \frac{ \lambda }{ c }\] now if the period increases will the wavelength decrease or increase (the upside down y called lambda is the wavelength).

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1All of these formulas are related so it's kind of neat you can rearrange them to find relations between them.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1So it's not c, if the period increases the wavelength will as well

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1That means the only answer will be? :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I had come back and say A

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Right A, seems best to me as well :)

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Yes, I know but we had to go through all the options to make sure.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Which produces a period of 0.1 seconds? a. a wave with a frequency of 5 Hz b. a wave with a wavelength of 7 m c. a wave with a frequency of 10 Hz d. a wave with a speed of 5 m/s

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Use the formula I provided earlier, \[T = \frac{ 1 }{ f }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well that means the answer can only be either a or c ha.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1and \[T = \frac{ \lambda }{ v }\]

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1No don't just assume that because I did not give you all the formulas

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0T=1/10. T= 0.1. The answer is C.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The frequency of a wave: a. increases with increasing period. b. decreases with increasing period. c. increases with increasing wavelength. d. a and c only.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Because frequency goes up and down.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1We're just going backwards from your first question here, do the same thing plug in some numbers

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[T = \frac{ 1 }{ f } \implies f = \frac{ 1 }{ T }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The number change up when plugging in the digits was pretty cool to see.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Are you sure? Would frequency increase if period increases? \[f = \frac{ 1 }{ T } = \frac{ 1 }{ 100000000 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh. Frequency decreases with the increased period. That earlier question had me a little confused.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The period of a vibrating object is halved if its frequency: a. triples. b. increases by one and a half times. c. increases by three and a half times. d. quadruples. e. doubles.
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