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anonymous

  • one year ago

The period of a wave: a. decreases with increasing frequency. b. increases with increasing frequency. c. increases with decreasing wavelength. d. a and c only. none of the above.

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  1. Astrophysics
    • one year ago
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    \[T = \frac{ 1 }{ f }\] what can we say about this formula (period)?

  2. anonymous
    • one year ago
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    That whichever number is below the 1 in the fraction is going to be the number itself?

  3. Astrophysics
    • one year ago
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    Plug in some large and small numbers and see what happens and relate it to your options.

  4. anonymous
    • one year ago
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    That whichever number is below the 1 in the fraction is going to be the number itself?

  5. Astrophysics
    • one year ago
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    \[f = \frac{ v }{ \lambda }\]

  6. Astrophysics
    • one year ago
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    I don't know what you mean, can you elaborate, I don't see how it has to do with your question?

  7. anonymous
    • one year ago
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    You asked what could I tell you about the first equation.

  8. Astrophysics
    • one year ago
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    \[T = \frac{ 1 }{ 10000000 }\] what happens if the frequency is that high, will the period decrease or increase?

  9. anonymous
    • one year ago
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    decrease.

  10. Astrophysics
    • one year ago
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    Yes, now if we have \[T = \frac{ 1 }{ 0.000000001 }\]

  11. anonymous
    • one year ago
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    Then we have a frequency that goes higher.

  12. Astrophysics
    • one year ago
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    Exactly!

  13. anonymous
    • one year ago
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    *increases

  14. anonymous
    • one year ago
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    The answer is D

  15. anonymous
    • one year ago
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    A & C

  16. anonymous
    • one year ago
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    oops no. A

  17. Astrophysics
    • one year ago
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    Now if we plug \[\huge T = \frac{ 1 }{ \frac{ v }{ \lambda } } \implies \frac{ \lambda }{ v }\] what happens?

  18. anonymous
    • one year ago
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    Im lost with everything passed T = 1

  19. anonymous
    • one year ago
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    First time in physics ....

  20. anonymous
    • one year ago
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    I know wavelength symbol.

  21. Astrophysics
    • one year ago
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    Well lets say the speed is constant, \[T = \frac{ \lambda }{ c }\] now if the period increases will the wavelength decrease or increase (the upside down y called lambda is the wavelength).

  22. anonymous
    • one year ago
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    Right

  23. Astrophysics
    • one year ago
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    All of these formulas are related so it's kind of neat you can rearrange them to find relations between them.

  24. anonymous
    • one year ago
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    indeed

  25. Astrophysics
    • one year ago
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    So it's not c, if the period increases the wavelength will as well

  26. Astrophysics
    • one year ago
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    That means the only answer will be? :)

  27. anonymous
    • one year ago
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    I had come back and say A

  28. Astrophysics
    • one year ago
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    Right A, seems best to me as well :)

  29. anonymous
    • one year ago
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    said*

  30. Astrophysics
    • one year ago
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    Yes, I know but we had to go through all the options to make sure.

  31. anonymous
    • one year ago
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    Which produces a period of 0.1 seconds? a. a wave with a frequency of 5 Hz b. a wave with a wavelength of 7 m c. a wave with a frequency of 10 Hz d. a wave with a speed of 5 m/s

  32. Astrophysics
    • one year ago
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    Use the formula I provided earlier, \[T = \frac{ 1 }{ f }\]

  33. anonymous
    • one year ago
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    Well that means the answer can only be either a or c ha.

  34. Astrophysics
    • one year ago
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    and \[T = \frac{ \lambda }{ v }\]

  35. Astrophysics
    • one year ago
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    No don't just assume that because I did not give you all the formulas

  36. Astrophysics
    • one year ago
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    Try it yourself

  37. anonymous
    • one year ago
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    T=1/10. T= 0.1. The answer is C.

  38. Astrophysics
    • one year ago
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    Looks good

  39. anonymous
    • one year ago
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    The frequency of a wave: a. increases with increasing period. b. decreases with increasing period. c. increases with increasing wavelength. d. a and c only.

  40. anonymous
    • one year ago
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    I am thinking d.

  41. anonymous
    • one year ago
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    Because frequency goes up and down.

  42. Astrophysics
    • one year ago
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    We're just going backwards from your first question here, do the same thing plug in some numbers

  43. Astrophysics
    • one year ago
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    \[T = \frac{ 1 }{ f } \implies f = \frac{ 1 }{ T }\]

  44. anonymous
    • one year ago
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    A

  45. anonymous
    • one year ago
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    The number change up when plugging in the digits was pretty cool to see.

  46. Astrophysics
    • one year ago
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    Are you sure? Would frequency increase if period increases? \[f = \frac{ 1 }{ T } = \frac{ 1 }{ 100000000 }\]

  47. anonymous
    • one year ago
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    Oh. Frequency decreases with the increased period. That earlier question had me a little confused.

  48. anonymous
    • one year ago
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    So, B.

  49. Astrophysics
    • one year ago
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    Yeah :)

  50. anonymous
    • one year ago
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    The period of a vibrating object is halved if its frequency: a. triples. b. increases by one and a half times. c. increases by three and a half times. d. quadruples. e. doubles.

  51. anonymous
    • one year ago
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    Doubles

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