The area of a rectangle is 54ft^2 and the length of the rectangle is 3ft more than twice the width. find the dimensions of the angle.
Length:?
Width:?

- anonymous

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- anonymous

@10115658

- anonymous

sorry man i can't help you on this one

- anonymous

aww really?

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## More answers

- anonymous

Do you have any idea how to set it up?

- anonymous

I honestly have no idea lol, that is why I tagged you in it, I've never done this equation before.

- anonymous

maybe factor it

- anonymous

I'm not sure lol

- anonymous

give me a sec

- anonymous

ok i figured it out

- anonymous

so set up an equation for this problem

- anonymous

How would I start that

- anonymous

ok lets use w to represent the unknown

- anonymous

so how do you find the length of a rectangle

- anonymous

L=P/2 * W?

- anonymous

sorry i meant to write area.
How do you find the area of a rectangle

- anonymous

A=wl

- anonymous

correct

- anonymous

so we called the width w. the question says the length is 3 feet more than twice the width.
what would you have to do to W to get that?

- anonymous

put it into a expression maybe?

- anonymous

like a algebraic expression

- anonymous

ya

- anonymous

so...3xn?

- anonymous

something around there

- anonymous

so it says the length is twice the width

- anonymous

we called width w.
so we have 2w

- anonymous

it also says that it's 3 feet more than that. what would you add to 2w to represent that?

- anonymous

2w + ?

- anonymous

2w+3?

- anonymous

correct.

- anonymous

2w+3=54ft^2?

- anonymous

So that represents our length.
What are you missing from that equation?

- anonymous

remember area= L x W

- anonymous

we're missing the width right?

- anonymous

correct, what does the equation look like?

- anonymous

is it going to be the same as the length? the 2w?

- anonymous

I'm not sure :l im very slow haha, I hate math

- anonymous

so we started by saying that w is the width

- anonymous

we multiplied that by 2 and added 3 to represent the length

- anonymous

I was going to say we are going to plug in w but there is nothing to plug in.

- anonymous

54 = (2w+3)w

- anonymous

I solve that right?

- anonymous

ya, do you understand how i got that equation though?

- anonymous

I got 54=5, and yes I understand now how you got the equation

- anonymous

or 54/5

- anonymous

nope

- anonymous

I can't really solve it then? because you add like terms right so 2+3 is 5 and then the 54 is just there.

- anonymous

multiply this out
(2w+3)w

- anonymous

6w

- anonymous

6w^2

- anonymous

nope, do you remember how to expand?

- anonymous

Nope

- anonymous

|dw:1433022042596:dw|

- anonymous

what's w times 2w?

- anonymous

3w^2?

- anonymous

or 2w^2

- anonymous

the only reason why I say that is because sometimes the w could be used as a 1 but I could be wrong

- anonymous

it's 2w^2

- anonymous

|dw:1433022177245:dw|

- anonymous

now what's w times 3?

- anonymous

3w

- anonymous

correct, so we have 2w^2 + 3w = 54

- anonymous

it looks like we have to factor this

- anonymous

so move everything to one side of the equation

- anonymous

Is it -6, an 9/2?

- anonymous

right so is the width -6 or 9/2?

- anonymous

-6?

- anonymous

is it possible to have a negative width?

- anonymous

nope

- anonymous

So what is it?

- anonymous

6?

- anonymous

nope

- anonymous

9/2?

- anonymous

what was the other value you got

- anonymous

9/2 is correct

- anonymous

so the width is 9/2 and the length is -6?

- anonymous

It says that the length is twice the width plus 3 more

- anonymous

so what should the length be?

- anonymous

12?

- anonymous

ok, what's 9/2 times 12?

- anonymous

54

- anonymous

good job

- anonymous

Thank you very much I appreciate you taking the time to work with me.

- anonymous

no problem

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