anonymous
  • anonymous
What are the x-intercepts of the quadratic function? y = x2 + x – 2 A. –2 and 1 B. 2 and 1 C. 1 D. 2 and –1 @pooja195
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
@mathmate
anonymous
  • anonymous
set y=0 and solve for x
anonymous
  • anonymous
can you explain on the drawing tool?

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More answers

anonymous
  • anonymous
|dw:1433021112375:dw|
anonymous
  • anonymous
So the x-intercept is where the function crosses the x-axis.
anonymous
  • anonymous
The x-axis is located where y=0
anonymous
  • anonymous
so set y=0 in the equation
anonymous
  • anonymous
this gives 0 = x^2 + x -2
anonymous
  • anonymous
okay!
anonymous
  • anonymous
now solve for x
anonymous
  • anonymous
im confused??
anonymous
  • anonymous
i barley started learning this!?
anonymous
  • anonymous
you have to factor the equation
anonymous
  • anonymous
???
anonymous
  • anonymous
x^2 + x - 2
anonymous
  • anonymous
oh ok
anonymous
  • anonymous
what two numbers equal 1 when you add them together, and equal -2 when you multiply them together?
anonymous
  • anonymous
-1?
anonymous
  • anonymous
nope
anonymous
  • anonymous
umm
anonymous
  • anonymous
give me two number that multiply together to get -2
anonymous
  • anonymous
1 times -2
anonymous
  • anonymous
ok, now add those together. what do you get
anonymous
  • anonymous
-3
anonymous
  • anonymous
nope. 1-2
anonymous
  • anonymous
-1
anonymous
  • anonymous
that's right, but we need a number that adds to one
anonymous
  • anonymous
what else multiplies together to get -2?
anonymous
  • anonymous
-1 and 2?
anonymous
  • anonymous
i am not sure? @1
anonymous
  • anonymous
@10115658
anonymous
  • anonymous
ok, now add them together
anonymous
  • anonymous
-3?
anonymous
  • anonymous
i mean 1
anonymous
  • anonymous
that's right.
anonymous
  • anonymous
so its D?
anonymous
  • anonymous
so now we have our factored equation (x+2) (x-1)
anonymous
  • anonymous
its -2 and 1
anonymous
  • anonymous
its A then?
anonymous
  • anonymous
correct, good job

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