readergirl12
  • readergirl12
What is the solution to the equation? (equation is below)
Mathematics
jamiebookeater
  • jamiebookeater
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readergirl12
  • readergirl12
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anonymous
  • anonymous
hello
readergirl12
  • readergirl12
Hey.

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anonymous
  • anonymous
The first thing you should do is expand 3/4(4c+16)
anonymous
  • anonymous
Do you know how to do that?
readergirl12
  • readergirl12
Not really..Could you show me?
anonymous
  • anonymous
|dw:1433023102916:dw|
anonymous
  • anonymous
so first multiply 4C times 3/4
anonymous
  • anonymous
|dw:1433023179671:dw|
readergirl12
  • readergirl12
It's zero.
anonymous
  • anonymous
nope.
anonymous
  • anonymous
ignore the C for a second
anonymous
  • anonymous
what is 4 times (3/4)?
readergirl12
  • readergirl12
It's 3.
anonymous
  • anonymous
correct now put the C back to get 3C
anonymous
  • anonymous
|dw:1433023330748:dw|
anonymous
  • anonymous
now multiply to get the second term
readergirl12
  • readergirl12
So 3/4 times 16?
anonymous
  • anonymous
yep
readergirl12
  • readergirl12
I got 12.
anonymous
  • anonymous
yep
anonymous
  • anonymous
so now the equation is 3C + 12 = 2C + 9
anonymous
  • anonymous
now solve for C
readergirl12
  • readergirl12
And how do I do that? I'm so sorry >.<
anonymous
  • anonymous
ok, so you want to get the C terms on one side of the equation and the non-C terms on the other side of the equation
anonymous
  • anonymous
So lets put the C terms on the left side
anonymous
  • anonymous
|dw:1433023540785:dw|
anonymous
  • anonymous
So what do you do you get rid of the 2C from the right side of the equation?
readergirl12
  • readergirl12
Subtract?
anonymous
  • anonymous
that's right, so subtract 2C from both sides of the equation
readergirl12
  • readergirl12
So the first one I subtract would be 2c-12?
anonymous
  • anonymous
nope
anonymous
  • anonymous
|dw:1433023787102:dw|
anonymous
  • anonymous
what does that leave you with?
readergirl12
  • readergirl12
Zero
anonymous
  • anonymous
huh?
anonymous
  • anonymous
what's 3C - 2C?
anonymous
  • anonymous
ignore the C term. what is 3-2?
readergirl12
  • readergirl12
Oh it's 1
anonymous
  • anonymous
now put the C back, we just get C
anonymous
  • anonymous
|dw:1433023979758:dw|
anonymous
  • anonymous
So what's the last step?
readergirl12
  • readergirl12
I don't know..Solve for C?
anonymous
  • anonymous
how do you get rid of the 12 on the left side of the equation?
readergirl12
  • readergirl12
Subtract.
anonymous
  • anonymous
|dw:1433024098852:dw|
anonymous
  • anonymous
C = ?
readergirl12
  • readergirl12
3? :o
anonymous
  • anonymous
nope. 9-12 = ?
readergirl12
  • readergirl12
-3
anonymous
  • anonymous
yep, so C is ?
readergirl12
  • readergirl12
-3
anonymous
  • anonymous
good job
readergirl12
  • readergirl12
Thanks.. xD

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