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readergirl12

  • one year ago

What is the solution to the equation? (equation is below)

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  1. readergirl12
    • one year ago
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  2. anonymous
    • one year ago
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    hello

  3. readergirl12
    • one year ago
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    Hey.

  4. anonymous
    • one year ago
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    The first thing you should do is expand 3/4(4c+16)

  5. anonymous
    • one year ago
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    Do you know how to do that?

  6. readergirl12
    • one year ago
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    Not really..Could you show me?

  7. anonymous
    • one year ago
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    |dw:1433023102916:dw|

  8. anonymous
    • one year ago
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    so first multiply 4C times 3/4

  9. anonymous
    • one year ago
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    |dw:1433023179671:dw|

  10. readergirl12
    • one year ago
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    It's zero.

  11. anonymous
    • one year ago
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    nope.

  12. anonymous
    • one year ago
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    ignore the C for a second

  13. anonymous
    • one year ago
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    what is 4 times (3/4)?

  14. readergirl12
    • one year ago
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    It's 3.

  15. anonymous
    • one year ago
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    correct now put the C back to get 3C

  16. anonymous
    • one year ago
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    |dw:1433023330748:dw|

  17. anonymous
    • one year ago
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    now multiply to get the second term

  18. readergirl12
    • one year ago
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    So 3/4 times 16?

  19. anonymous
    • one year ago
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    yep

  20. readergirl12
    • one year ago
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    I got 12.

  21. anonymous
    • one year ago
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    yep

  22. anonymous
    • one year ago
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    so now the equation is 3C + 12 = 2C + 9

  23. anonymous
    • one year ago
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    now solve for C

  24. readergirl12
    • one year ago
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    And how do I do that? I'm so sorry >.<

  25. anonymous
    • one year ago
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    ok, so you want to get the C terms on one side of the equation and the non-C terms on the other side of the equation

  26. anonymous
    • one year ago
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    So lets put the C terms on the left side

  27. anonymous
    • one year ago
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    |dw:1433023540785:dw|

  28. anonymous
    • one year ago
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    So what do you do you get rid of the 2C from the right side of the equation?

  29. readergirl12
    • one year ago
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    Subtract?

  30. anonymous
    • one year ago
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    that's right, so subtract 2C from both sides of the equation

  31. readergirl12
    • one year ago
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    So the first one I subtract would be 2c-12?

  32. anonymous
    • one year ago
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    nope

  33. anonymous
    • one year ago
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    |dw:1433023787102:dw|

  34. anonymous
    • one year ago
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    what does that leave you with?

  35. readergirl12
    • one year ago
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    Zero

  36. anonymous
    • one year ago
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    huh?

  37. anonymous
    • one year ago
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    what's 3C - 2C?

  38. anonymous
    • one year ago
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    ignore the C term. what is 3-2?

  39. readergirl12
    • one year ago
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    Oh it's 1

  40. anonymous
    • one year ago
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    now put the C back, we just get C

  41. anonymous
    • one year ago
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    |dw:1433023979758:dw|

  42. anonymous
    • one year ago
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    So what's the last step?

  43. readergirl12
    • one year ago
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    I don't know..Solve for C?

  44. anonymous
    • one year ago
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    how do you get rid of the 12 on the left side of the equation?

  45. readergirl12
    • one year ago
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    Subtract.

  46. anonymous
    • one year ago
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    |dw:1433024098852:dw|

  47. anonymous
    • one year ago
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    C = ?

  48. readergirl12
    • one year ago
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    3? :o

  49. anonymous
    • one year ago
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    nope. 9-12 = ?

  50. readergirl12
    • one year ago
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    -3

  51. anonymous
    • one year ago
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    yep, so C is ?

  52. readergirl12
    • one year ago
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    -3

  53. anonymous
    • one year ago
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    good job

  54. readergirl12
    • one year ago
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    Thanks.. xD

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