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anonymous

  • one year ago

Solve. x2 – 8x + 4 = 0

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  1. anonymous
    • one year ago
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    i am going to post the answer choices!:)

  2. pooja195
    • one year ago
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    what multiplies to 4 and adds up to -8?

  3. anonymous
    • one year ago
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    4?

  4. pooja195
    • one year ago
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    AND?

  5. anonymous
    • one year ago
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    -4?

  6. pooja195
    • one year ago
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    no

  7. anonymous
    • one year ago
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    um 2

  8. pooja195
    • one year ago
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    -4 and 2 are right lol sorry for caps >_< (x-4)(x+2) Solve

  9. anonymous
    • one year ago
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    4 and -2

  10. pooja195
    • one year ago
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    Good :)

  11. anonymous
    • one year ago
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    |dw:1433024849017:dw|

  12. anonymous
    • one year ago
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    @pooja195 these are he answer choices!

  13. pooja195
    • one year ago
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    >_< GRRR!!! they want the quadratic formula TTT_TT

  14. pooja195
    • one year ago
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    ok B) what are the a b c values? :)

  15. anonymous
    • one year ago
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    x^2 8 and 4

  16. pooja195
    • one year ago
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    fair enough a=1 b=8 c=4 \[\huge~x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a } \]

  17. pooja195
    • one year ago
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    \[\huge~x=\frac{ -(8)\pm \sqrt{(8)^2-4(1)(4)} }{ 2(4) }\]

  18. anonymous
    • one year ago
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    okay!

  19. pooja195
    • one year ago
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    eh it looks overwhelming :/ (8)^2−4(1)(4)=?

  20. anonymous
    • one year ago
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    48?

  21. anonymous
    • one year ago
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    @pooja195

  22. pooja195
    • one year ago
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    \[\huge~x=\frac{ -8 \pm \sqrt{48} }{ 2}\]

  23. pooja195
    • one year ago
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    @jagr2713 how do i finsih this?

  24. anonymous
    • one year ago
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    @jagr2713

  25. pooja195
    • one year ago
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    @TheSmartOne !!!!!

  26. anonymous
    • one year ago
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    @danial.sheikh

  27. pooja195
    • one year ago
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    @mathmate T_T

  28. anonymous
    • one year ago
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    wait

  29. geerky42
    • one year ago
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    HINT: \(48 = 16\cdot3\)

  30. geerky42
    • one year ago
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    @pooja195

  31. mathmate
    • one year ago
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    \(\huge~x=\frac{ -(-8) \pm \sqrt{48} }{ 2}\)

  32. mathmate
    • one year ago
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    which simplifies to: \(\huge~x=4 \pm 2\sqrt{3} \) using \(\large \sqrt{a^2b}=a\sqrt b\)

  33. anonymous
    • one year ago
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    @pooja195 so what is the next step?

  34. pooja195
    • one year ago
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    Look at what @mathmate showed u .-.

  35. anonymous
    • one year ago
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    okay!

  36. anonymous
    • one year ago
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    so A?

  37. pooja195
    • one year ago
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    go_od job :) it is A

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