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## anonymous one year ago A triangle is placed in a semicircle with a radius of 5 ft, as shown below. Find the area of the shaded region. Use the value 3.14 for pi and do not round your answer.

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1. anonymous

2. anonymous

area of triangle$=\frac{ 1 }{ 2 }\times base \times altitude=?$ area of semi circle$=\frac{ \pi \times r^2 }{ 2 }=?$ then subtract

3. anonymous

Do I find the answer for both

4. anonymous

Do you know that area of circle is$Area = πr^2$ and the area of triangle is $Area of \triangle = \frac{ 1 }{ 2 } * base * height$ Then now what you have the two areas with your hands , to get the shaded region you just simply subtract the smaller shape from the larger one , which in this question Larger : the semicircle and the smaller one is the triangle ! Now to calculate just subs. with given values $Area of semicircle = \frac{ 1 }{ 2 } * π * 5^2 = 12.5$ And $Area of \triangle = \frac{ 1 }{ 2 } * 10 * 5 = 25$ Now the shaded region is :$Area of shaded region : 12.5π - 25$ Let me know if you got it :)

5. anonymous

I completely understand :) so I subtract 12.5 pi - 25 and the answer is 14.26

6. anonymous

@Omar_Elboredy

7. anonymous

area of triangle$=\frac{ 1 }{2 }\times10\times 5=25$ area of semi circle$=\frac{ \pi r^2 }{ 2 }=\frac{ 3.14\times25 }{ 2 }=\frac{ 78.50 }{ 2 }=39.25$ reqd. area=39.25-25=?

8. anonymous

Exactly ! :D

9. anonymous

I have no idea who is right lol...

10. anonymous

both are correct

11. anonymous

@surjithayer would the answer be ft, ft^2 or ft^3?

12. anonymous

area is always in square units

13. anonymous

Thank you the both of ya'll!

14. anonymous

if I could give you both metals I would!

15. anonymous

Welcomes ! :) Feel free to ask anytime :D

16. anonymous

Will you help me with one more? @Omar_Elboredy

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