anonymous
  • anonymous
Calculate the discriminant and use it to determine how many real-number roots the equation has. 3x2 – 6x + 4 = 0 A. three real-number roots B. no real-number roots C. one real-number root D. two real-number roots
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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mathmate
  • mathmate
Can you identify the values of a, b and c as @pooja195 showed you?
mathmate
  • mathmate
You'll need them to calculate the discriminant, which in turn is necessary to find the number of real/complex roots.
anonymous
  • anonymous
no real number trust me im in college I took all about this

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anonymous
  • anonymous
3x^2,6x and 4
anonymous
  • anonymous
@mathmate
anonymous
  • anonymous
are you there? @mathmate
mathmate
  • mathmate
The powers of x do not count, because it comes from ax^2+bx+c, so a,b,c do not contain the powers of x, just the coefficients will do.
anonymous
  • anonymous
ok
mathmate
  • mathmate
But you need to include the signs, so it is a=3, b=-6 c=4
mathmate
  • mathmate
Can you look up the formula for discriminant, which @pooja195 gave you?
anonymous
  • anonymous
ummm, where do i get that? shes ofline im prety sure!!
mathmate
  • mathmate
Your previous post.
anonymous
  • anonymous
it doesnt let me for some reason , can you try??
mathmate
  • mathmate
ok, you'll be needing this for you test or exam, so try to get familiar with it, if you can: discriminant = \(b^2-4ac\)
anonymous
  • anonymous
ok
mathmate
  • mathmate
if the discriminant is negative, all roots are complex. If the discriminant is positive, there will be two distinct (different) real roots if the discriminant is zero, there will be two coincident (same value) real roots.
anonymous
  • anonymous
okayyy!
anonymous
  • anonymous
so my guess is c? @mathmate
mathmate
  • mathmate
Please do not guess! Did you calculate the determinant?
mathmate
  • mathmate
* discriminant

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