Calculate the discriminant and use it to determine how many real-number roots the equation has. 3x2 – 6x + 4 = 0 A. three real-number roots B. no real-number roots C. one real-number root D. two real-number roots

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Calculate the discriminant and use it to determine how many real-number roots the equation has. 3x2 – 6x + 4 = 0 A. three real-number roots B. no real-number roots C. one real-number root D. two real-number roots

Mathematics
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Can you identify the values of a, b and c as @pooja195 showed you?
You'll need them to calculate the discriminant, which in turn is necessary to find the number of real/complex roots.
no real number trust me im in college I took all about this

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3x^2,6x and 4
are you there? @mathmate
The powers of x do not count, because it comes from ax^2+bx+c, so a,b,c do not contain the powers of x, just the coefficients will do.
ok
But you need to include the signs, so it is a=3, b=-6 c=4
Can you look up the formula for discriminant, which @pooja195 gave you?
ummm, where do i get that? shes ofline im prety sure!!
Your previous post.
it doesnt let me for some reason , can you try??
ok, you'll be needing this for you test or exam, so try to get familiar with it, if you can: discriminant = \(b^2-4ac\)
ok
if the discriminant is negative, all roots are complex. If the discriminant is positive, there will be two distinct (different) real roots if the discriminant is zero, there will be two coincident (same value) real roots.
okayyy!
so my guess is c? @mathmate
Please do not guess! Did you calculate the determinant?
* discriminant

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