## anonymous one year ago How can I solve for x in this equation: ln(x) + ln(x-1) = 1

1. anonymous

$\ln x \left( x-1 \right)=1$

2. geerky42

For left side of a equation, you can apply this property:$\log(a)+\log(b) = \log(ab)$

3. anonymous

I know that it first simplifies to $\ln (x(x-1))=1$ and then to... $x(x-1)=e$

4. anonymous

5. geerky42

Arrange, then you can apply quadratic formula.

6. geerky42

damn you so fast @surjithayer

7. anonymous

Of course! Thank you both!! :D haha