anonymous
  • anonymous
How can I find the exact value of: sec[arctan(2)]
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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jim_thompson5910
  • jim_thompson5910
|dw:1433030295384:dw|
jim_thompson5910
  • jim_thompson5910
let theta = arctan(2) this means that tan(theta) = 2 = 2/1 recall that tangent deals with opposite/adjacent, so because tan(theta) = 2/1, we know |dw:1433030381643:dw|
jim_thompson5910
  • jim_thompson5910
are you able to find the length of the hypotenuse?

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anonymous
  • anonymous
yes
jim_thompson5910
  • jim_thompson5910
the question is direct at @Tracy96
anonymous
  • anonymous
@jim_thompson5910 yep! I got it! So I gotta use Pythagorus, correct?
anonymous
  • anonymous
length^2+width^2=hypotenuse^ 2
jim_thompson5910
  • jim_thompson5910
correct @Tracy96
jim_thompson5910
  • jim_thompson5910
you have to use a^2 + b^2 = c^2 a = 1 b = 2 c = unknown for now |dw:1433030530767:dw|
anonymous
  • anonymous
@henryli is correct too!!
anonymous
  • anonymous
corect
anonymous
  • anonymous
@jim_thompson5910 right, so hypotenuse would be sqrt(5) ?
anonymous
  • anonymous
yep
jim_thompson5910
  • jim_thompson5910
yes that is correct |dw:1433030615675:dw|
jim_thompson5910
  • jim_thompson5910
now because I let theta = arctan(2), this means sec[arctan(2)] turns into sec(theta)
jim_thompson5910
  • jim_thompson5910
use the drawing to compute sec(theta)
anonymous
  • anonymous
@jim_thompson5910 Mhmm, and sec is just 1/cos right?
jim_thompson5910
  • jim_thompson5910
correct
anonymous
  • anonymous
correct
jim_thompson5910
  • jim_thompson5910
you can also think of secant as hypotenuse/adjacent
anonymous
  • anonymous
yeah
anonymous
  • anonymous
@jim_thompson5910 True!!
anonymous
  • anonymous
@jim_thompson5910 Thanks so much!! I really appreciate it!!
jim_thompson5910
  • jim_thompson5910
sounds like you got the final answer, yw

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