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anonymous

  • one year ago

How can I find the exact value of: sec[arctan(2)]

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  1. jim_thompson5910
    • one year ago
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    |dw:1433030295384:dw|

  2. jim_thompson5910
    • one year ago
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    let theta = arctan(2) this means that tan(theta) = 2 = 2/1 recall that tangent deals with opposite/adjacent, so because tan(theta) = 2/1, we know |dw:1433030381643:dw|

  3. jim_thompson5910
    • one year ago
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    are you able to find the length of the hypotenuse?

  4. anonymous
    • one year ago
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    yes

  5. jim_thompson5910
    • one year ago
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    the question is direct at @Tracy96

  6. anonymous
    • one year ago
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    @jim_thompson5910 yep! I got it! So I gotta use Pythagorus, correct?

  7. anonymous
    • one year ago
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    length^2+width^2=hypotenuse^ 2

  8. jim_thompson5910
    • one year ago
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    correct @Tracy96

  9. jim_thompson5910
    • one year ago
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    you have to use a^2 + b^2 = c^2 a = 1 b = 2 c = unknown for now |dw:1433030530767:dw|

  10. anonymous
    • one year ago
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    @henryli is correct too!!

  11. anonymous
    • one year ago
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    corect

  12. anonymous
    • one year ago
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    @jim_thompson5910 right, so hypotenuse would be sqrt(5) ?

  13. anonymous
    • one year ago
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    yep

  14. jim_thompson5910
    • one year ago
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    yes that is correct |dw:1433030615675:dw|

  15. jim_thompson5910
    • one year ago
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    now because I let theta = arctan(2), this means sec[arctan(2)] turns into sec(theta)

  16. jim_thompson5910
    • one year ago
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    use the drawing to compute sec(theta)

  17. anonymous
    • one year ago
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    @jim_thompson5910 Mhmm, and sec is just 1/cos right?

  18. jim_thompson5910
    • one year ago
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    correct

  19. anonymous
    • one year ago
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    correct

  20. jim_thompson5910
    • one year ago
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    you can also think of secant as hypotenuse/adjacent

  21. anonymous
    • one year ago
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    yeah

  22. anonymous
    • one year ago
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    @jim_thompson5910 True!!

  23. anonymous
    • one year ago
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    @jim_thompson5910 Thanks so much!! I really appreciate it!!

  24. jim_thompson5910
    • one year ago
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    sounds like you got the final answer, yw

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