Find the area of a regular nonagon with an apothem 16.5 inches long and a side 19 inches long. [A] 1410.8 in2 [B] 171.0 in2 [C] 2821.5 in2 [D] 256.0 in2

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Find the area of a regular nonagon with an apothem 16.5 inches long and a side 19 inches long. [A] 1410.8 in2 [B] 171.0 in2 [C] 2821.5 in2 [D] 256.0 in2

Mathematics
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Is this the right formula A=9/\[9/4 a ^{2}(180ยบ/9)
You will have 9 triangles that all look like this |dw:1433031577045:dw| they will arrange to form a nonagon
find the area of 1 triangle, then multiply that area by 9

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Oh ok
And what formula would I use for that?
A = 1/2 bh
yes
oh ok! And 19 would be the base, while the 16.5 is the height, correct?
correct, what area do you get?
Um, the final answer would be A right? But the area I got was 156.75
And then when I multiplied that by 9, I got 1210,75 which would round up to 1410.8
very good, you nailed it
Thank you!

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