Calculate the discriminant and use it to determine how many real-number roots the equation has. 3x2 – 6x + 4 = 0 A. three real-number roots B. no real-number roots C. one real-number root D. two real-number roots

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Calculate the discriminant and use it to determine how many real-number roots the equation has. 3x2 – 6x + 4 = 0 A. three real-number roots B. no real-number roots C. one real-number root D. two real-number roots

Mathematics
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Three
I think?
can you tag someone else to see what they think to??
Can't be 3. the highest exponent is 2, so you there can only be 0, 1, or 2 solutions. The discriminant is b² - 4ac. - If b² - 4ac = 0, there is 1 solution. - If b² - 4ac is positive, there are 2 solutions. - If b² - 4ac is negative, there are 0 solutions.
my answer whould be c?
No. What did you get for the discriminant.
sorry, i meant to say d!:)
I am with peachpi. They asked you to find discriminant. You MUST have it first.
i am not sure how to do that, will you helpme??
For the equation ax² + bx + c = 0, the discriminant is b² - 4ac. For your equation, a = 3, b = -6, and c = 4.
okay
So what's b²-4ac?
um is that the abc equation?? @peachpi
I'm not sure what the a,b,c equation is. I gave you the numbers above. You just need to plug them into the expression b²-4ac to get the discriminant.
-6^2-4(3)(4) @peachpi
is this correct? @peachpi
yes and now you need to simplify it to a single number.
|dw:1433034729464:dw|
ok. in my first response I listed all the possible scenarios. How many solutions does your equation have?
Which is your discriminant: positive, negative, or 0?
negative
ok. so looking above, how many solutions are there for a negative discriminant?
one?
- If b² - 4ac = 0, there is 1 solution. - If b² - 4ac is positive, there are 2 solutions. - If b² - 4ac is negative, there are 0 solutions.
no solutions
right
so b?
yep
https://www.wolframalpha.com/input/?i=factor++3x2+%E2%80%93+6x+%2B+4+%3D+0
no real roots

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