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anonymous

  • one year ago

Unit 6 Rational Expression Multiply. (a - 4) x 2a a^2 - 4a (a + 3)(a - 1) A. 2a^2 a - 1 B. 2 a - 1 C. 2a a + 1 D. 2a 2 - 1

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  1. geerky42
    • one year ago
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    Can you take screenshot of problem? Because it's hard to read here...

  2. anonymous
    • one year ago
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    I can't it doesn't work I will trying and use equation

  3. geerky42
    • one year ago
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    Why doesn't screenshot work? What computer are you using?/

  4. anonymous
    • one year ago
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    \[\frac{ (a - 4) }{ a^2 - 4a } x \frac{ 2a }{ (a + 3)(a - 1) }\]

  5. geerky42
    • one year ago
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    You can factor \(a^2-4a\), just factor \(a\) out; \[a^2-4a\quad\Longrightarrow\quad a(a-4)\]

  6. geerky42
    • one year ago
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    So you have \[\frac{ (a - 4) }{ a(a - 4) } \times \frac{ 2a }{ (a + 3)(a - 1) }\]

  7. anonymous
    • one year ago
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    okay so next is to cross out (a - 4)

  8. geerky42
    • one year ago
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    \[\frac{ \cancel{(a - 4)} }{ a\cancel{(a - 4)} } \times \frac{ 2a }{ (a + 3)(a - 1) }\]\[\dfrac{1}{a}\times\frac{ 2a }{ (a + 3)(a - 1) } \]

  9. geerky42
    • one year ago
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    You can also cancel a out.

  10. geerky42
    • one year ago
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    \[\dfrac{1}{\cancel a}\times\frac{ 2\cancel a }{ (a + 3)(a - 1) } \]

  11. geerky42
    • one year ago
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    Now you are left with \(\dfrac2{(a+3)(a-1)}\)

  12. anonymous
    • one year ago
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    okay cool I didn't know that

  13. geerky42
    • one year ago
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    That's weird, it's not in options.

  14. geerky42
    • one year ago
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    Or is it?

  15. anonymous
    • one year ago
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    I don't know it doesn't show in my text book

  16. geerky42
    • one year ago
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    What computer are you using?

  17. anonymous
    • one year ago
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    HP

  18. geerky42
    • one year ago
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    Then there should be PrtScr on your keyboard, right? you can take screenshot by press that

  19. geerky42
    • one year ago
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    then open MS paint and paste

  20. anonymous
    • one year ago
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    I know that but I broke the button

  21. geerky42
    • one year ago
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    ah okay.

  22. geerky42
    • one year ago
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    well, I don't know what to do from here, sorry.

  23. anonymous
    • one year ago
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    it okay thanks for your help

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