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MeowLover17

  • one year ago

Part A: Using the graph above, create a system of inequalities that only contain points A and E in the overlapping shaded regions. Explain how the lines will be graphed and shaded on the coordinate grid above. (5 points) Part B: Explain how to verify that the points A and E are solutions to the system of inequalities created in Part A. (3 points) Part C: William can only attend a school in his designated zone. William's zone is defined by y < -x - 1. Explain how you can identify the schools that William is allowed to attend. (2 points)

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  1. MeowLover17
    • one year ago
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  2. MeowLover17
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    @Loser66

  3. MeowLover17
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    @Hero

  4. MeowLover17
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    @Z4K4R1Y4

  5. MeowLover17
    • one year ago
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    Hey Z4 Got any input??

  6. MeowLover17
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    @jim_thompson5910

  7. MeowLover17
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    Hmm

  8. Z4K4R1Y4
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    |dw:1433034312051:dw|

  9. MeowLover17
    • one year ago
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    So what do i answer for part A?

  10. MeowLover17
    • one year ago
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    Like where is the system of inequalities or how do i make it???

  11. MeowLover17
    • one year ago
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    Jim please help

  12. jim_thompson5910
    • one year ago
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    you can make up anything you want BUT it has to be where the solution for both has to have A and E in it (and only those two points)

  13. jim_thompson5910
    • one year ago
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    |dw:1433034502120:dw|

  14. jim_thompson5910
    • one year ago
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    |dw:1433034513862:dw|

  15. jim_thompson5910
    • one year ago
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    here is one possibility |dw:1433034550716:dw|

  16. jim_thompson5910
    • one year ago
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    notice how it's the combination of two inequalities

  17. MeowLover17
    • one year ago
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    So how would i write that as a system of inequalities??

  18. MeowLover17
    • one year ago
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    I dont understand how to answer it :/

  19. jim_thompson5910
    • one year ago
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    what two points lie above point E? ignore the other points A through F

  20. MeowLover17
    • one year ago
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    (3,2) (3,3)

  21. jim_thompson5910
    • one year ago
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    ok I'm going to toss out (3,3) and replace it with (4,3) that way we can draw a line through those two points. This line will be completely above point E

  22. jim_thompson5910
    • one year ago
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    what is the equation of this line?

  23. MeowLover17
    • one year ago
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    Okay.

  24. MeowLover17
    • one year ago
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    y=x

  25. jim_thompson5910
    • one year ago
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    nope

  26. MeowLover17
    • one year ago
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    I know the slope goes up by 1, but im not sure of the y-intercept.

  27. MeowLover17
    • one year ago
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    y=x-2

  28. MeowLover17
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    Is that the equation of the line?

  29. jim_thompson5910
    • one year ago
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  30. jim_thompson5910
    • one year ago
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    what is the equation of that green line?

  31. MeowLover17
    • one year ago
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    y=x-1

  32. MeowLover17
    • one year ago
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    am i wrong o-o

  33. jim_thompson5910
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    yep y = x-1

  34. jim_thompson5910
    • one year ago
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    we want to shade below this line, so we could have y < x-1

  35. MeowLover17
    • one year ago
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    Okay

  36. MeowLover17
    • one year ago
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    So now i'm guessing we have to make another line with 2 points under A then shade where they overlap receiving the system of inequalities??

  37. jim_thompson5910
    • one year ago
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    that is correct

  38. jim_thompson5910
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    something like this

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  39. MeowLover17
    • one year ago
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    Indeed.

  40. MeowLover17
    • one year ago
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    So could help me create the answer to part?

  41. jim_thompson5910
    • one year ago
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    I'll brb, but I can do so when I get back

  42. MeowLover17
    • one year ago
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    ok i'll be waiting here

  43. MeowLover17
    • one year ago
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    Part A: So to graph the two lines first i must chose two points above points E, in this case i chose points (3,2) and (4,3), now i must draw the line going through these points and i should hit the y-axis at -1. Next i must choose two points under point A, so i choose (2,-4) and (3,-5) one i've drawn the line through these points i should hit the y-axis at -2. Now i must shade where both A, and E are within these instersecting lines. Which would be on the right side of this graph. Equations= y=x-1 & y=-x-2

  44. jim_thompson5910
    • one year ago
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    ok back yes the two equations are y = x-1 and y = -x-2 the inequalities are y < x-1 and y > -x-2

  45. MeowLover17
    • one year ago
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    Is that proper?

  46. jim_thompson5910
    • one year ago
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    graphing both inequalities at the same time gives you the shaded region |dw:1433036051038:dw|

  47. jim_thompson5910
    • one year ago
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    proper? what do you mean?

  48. MeowLover17
    • one year ago
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    @jim_thompson5910 Sorry i lost connection

  49. jim_thompson5910
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    thats ok

  50. jim_thompson5910
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    hopefully you see how I'm getting what I wrote above

  51. MeowLover17
    • one year ago
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    Okay so i meant is my answer for Part A, okay?

  52. MeowLover17
    • one year ago
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    Yea i understand.

  53. jim_thompson5910
    • one year ago
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    they want inequalities, not equations

  54. jim_thompson5910
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    but the equations are useful in forming the boundaries

  55. MeowLover17
    • one year ago
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    oh ok

  56. MeowLover17
    • one year ago
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    So was my answer for part A feasible?

  57. jim_thompson5910
    • one year ago
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    it's close to being complete

  58. MeowLover17
    • one year ago
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    I put the inequalities under the equations part on my worksheet.

  59. MeowLover17
    • one year ago
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    What else shall i add?

  60. jim_thompson5910
    • one year ago
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    add in info about the inequalities and their shaded regions

  61. MeowLover17
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    Yea i did, but I'm not sure how to explain the "shaded" regions.

  62. jim_thompson5910
    • one year ago
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    equation |dw:1433036725634:dw|

  63. jim_thompson5910
    • one year ago
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    inequality |dw:1433036745339:dw|

  64. jim_thompson5910
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    the inequality includes the shaded region which extends forever downward and to the right (below the line y = x-1)

  65. MeowLover17
    • one year ago
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    Okay i see the difference between an inequality and equation, for an inequality you must shade or make dashed depending on if its equal to or not but for an equation you just draw the line.

  66. jim_thompson5910
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    correct, I forgot about that part

  67. jim_thompson5910
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    since y < x-1 has no line under the < sign, we need a dashed boundary line

  68. MeowLover17
    • one year ago
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    Yes

  69. jim_thompson5910
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    but you can easily make it \[\Large y \le x-1\]

  70. MeowLover17
    • one year ago
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    Okay so let me show you my answer for part A: Its the same as i showed above just with the inequalities underneath it because i don't know what more to explain.

  71. MeowLover17
    • one year ago
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    This is for an online course so i can't draw graphs or anything i just type explanations :/

  72. jim_thompson5910
    • one year ago
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    then do your best to describe the equations/graphs. So mention the points involved and the direction of the shading, and the boundary line type

  73. jim_thompson5910
    • one year ago
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    |dw:1433036996621:dw| this boundary line goes through (3,2) and (4,3) it is a dashed boundary line (assuming you go with y < x-1) the shading is below the boundary line

  74. MeowLover17
    • one year ago
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    Okay let me explain it here then ill transcribe it. Part A: Continuation - After graphing y<x-1 i should shade below this line, i can figure this out by testing points above or below the line, i've figured out that points above the line don't work but those underneath do, so this is why i've shaded below y<x-1, same for the line y>-x-2, i shaded above it because when i test points below it does not work, now i can shade infinitley if i wanted too, but i am only shading where both shades meet from y>-x-2 and y<x-1 to receive the system of inequalities...

  75. MeowLover17
    • one year ago
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    If i add that on to my first answer does it make it complete?

  76. jim_thompson5910
    • one year ago
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    yes that wraps up part A

  77. MeowLover17
    • one year ago
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    Okay now could you help me answer parts B and C???

  78. jim_thompson5910
    • one year ago
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    Part B: Explain how to verify that the points A and E are solutions to the system of inequalities created in Part A.

  79. jim_thompson5910
    • one year ago
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    I'll show you how to verify point A and I'll let you verify point E

  80. MeowLover17
    • one year ago
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    K

  81. jim_thompson5910
    • one year ago
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    verifying point A point A is (x,y) = (2,-3) y < x-1 -3 < 2-1 ... plug in (x,y) = (2,-3) -3 < 1 ... this is true ------------ y > -x - 2 -3 > -2 - 2 ... plug in (x,y) = (2,-3) -3 > -4 ... this is true ------------- since y < x-1 AND y > -x - 2 are true at the same time for the ordered pair (2,-3), this confirms that point A is indeed in the solution set of this system of inequalities

  82. MeowLover17
    • one year ago
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    Oh i see so you just tested point A for both inequalities and it proved true.

  83. MeowLover17
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    Now i would have to do the same for E

  84. MeowLover17
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    right?

  85. jim_thompson5910
    • one year ago
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    correct

  86. MeowLover17
    • one year ago
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    Okay do i have to show this work or can i just explain it for part B?

  87. jim_thompson5910
    • one year ago
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    showing work is always a good idea, but I guess you could explain it if you want. It will depend on how the teacher wants it

  88. MeowLover17
    • one year ago
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    Okay ill just show your work for A then explain for E.

  89. MeowLover17
    • one year ago
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    Okay now on to the final part C

  90. jim_thompson5910
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    Part C: William can only attend a school in his designated zone. William's zone is defined by y < -x - 1. Explain how you can identify the schools that William is allowed to attend.

  91. jim_thompson5910
    • one year ago
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    so the goal here is to figure out which points (A through F) satisfy y < -x-1

  92. MeowLover17
    • one year ago
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    oKAY

  93. jim_thompson5910
    • one year ago
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    and you can use steps similar to what I had done in part B

  94. MeowLover17
    • one year ago
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    Btw pOINTS a THROUGH f ARE SCHOOLS in a city

  95. MeowLover17
    • one year ago
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    So do i just test all points in y>1-x to solve for c??

  96. jim_thompson5910
    • one year ago
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    you mean y < -x-1, right?

  97. MeowLover17
    • one year ago
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    Oh okay so my Answer for Part C would look like Part C: William can only attend schools that satisfy his zone which is y<-x-1, to figure out which schools would satisfy this i must plug in points A through F into this inequality and see which are true, those that are true are schools that William can attend those that are false or don't make sense are those that he can not attend.

  98. MeowLover17
    • one year ago
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    Is this correct???

  99. jim_thompson5910
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    so which points make y < -x-1 true?

  100. jim_thompson5910
    • one year ago
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    you provided the explanation as to how to find the points, but I think they also want the points listed

  101. MeowLover17
    • one year ago
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    It doesn't say that.

  102. MeowLover17
    • one year ago
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    It says "Explain how you can Identify the schools that william is allowed to attend" Not list the schools

  103. MeowLover17
    • one year ago
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    So does that mean my answer is correct???

  104. jim_thompson5910
    • one year ago
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    yeah if they don't want the list, then you have it completed

  105. MeowLover17
    • one year ago
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    Okay i have one more question could you help me on it??

  106. jim_thompson5910
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    ok

  107. jim_thompson5910
    • one year ago
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    what's the question?

  108. MeowLover17
    • one year ago
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    Oh, its like a whole other problem with parts a,b,c

  109. MeowLover17
    • one year ago
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    Could you give me about 10 minutes or so, i just wanna transcribe the work on here to my worksheet.

  110. jim_thompson5910
    • one year ago
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    alright

  111. MeowLover17
    • one year ago
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    Thanks

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