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MeowLover17
 one year ago
Part A: Using the graph above, create a system of inequalities that only contain points A and E in the overlapping shaded regions. Explain how the lines will be graphed and shaded on the coordinate grid above. (5 points)
Part B: Explain how to verify that the points A and E are solutions to the system of inequalities created in Part A. (3 points)
Part C: William can only attend a school in his designated zone. William's zone is defined by y < x  1. Explain how you can identify the schools that William is allowed to attend. (2 points)
MeowLover17
 one year ago
Part A: Using the graph above, create a system of inequalities that only contain points A and E in the overlapping shaded regions. Explain how the lines will be graphed and shaded on the coordinate grid above. (5 points) Part B: Explain how to verify that the points A and E are solutions to the system of inequalities created in Part A. (3 points) Part C: William can only attend a school in his designated zone. William's zone is defined by y < x  1. Explain how you can identify the schools that William is allowed to attend. (2 points)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hey Z4 Got any input??

Z4K4R1Y4
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433034312051:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So what do i answer for part A?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Like where is the system of inequalities or how do i make it???

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1you can make up anything you want BUT it has to be where the solution for both has to have A and E in it (and only those two points)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1dw:1433034502120:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1dw:1433034513862:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1here is one possibility dw:1433034550716:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1notice how it's the combination of two inequalities

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So how would i write that as a system of inequalities??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I dont understand how to answer it :/

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1what two points lie above point E? ignore the other points A through F

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1ok I'm going to toss out (3,3) and replace it with (4,3) that way we can draw a line through those two points. This line will be completely above point E

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1what is the equation of this line?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know the slope goes up by 1, but im not sure of the yintercept.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is that the equation of the line?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1what is the equation of that green line?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1we want to shade below this line, so we could have y < x1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So now i'm guessing we have to make another line with 2 points under A then shade where they overlap receiving the system of inequalities??

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1that is correct

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1something like this

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So could help me create the answer to part?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1I'll brb, but I can do so when I get back

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok i'll be waiting here

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Part A: So to graph the two lines first i must chose two points above points E, in this case i chose points (3,2) and (4,3), now i must draw the line going through these points and i should hit the yaxis at 1. Next i must choose two points under point A, so i choose (2,4) and (3,5) one i've drawn the line through these points i should hit the yaxis at 2. Now i must shade where both A, and E are within these instersecting lines. Which would be on the right side of this graph. Equations= y=x1 & y=x2

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1ok back yes the two equations are y = x1 and y = x2 the inequalities are y < x1 and y > x2

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1graphing both inequalities at the same time gives you the shaded region dw:1433036051038:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1proper? what do you mean?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@jim_thompson5910 Sorry i lost connection

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1hopefully you see how I'm getting what I wrote above

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay so i meant is my answer for Part A, okay?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1they want inequalities, not equations

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1but the equations are useful in forming the boundaries

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So was my answer for part A feasible?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1it's close to being complete

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I put the inequalities under the equations part on my worksheet.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What else shall i add?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1add in info about the inequalities and their shaded regions

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yea i did, but I'm not sure how to explain the "shaded" regions.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1equation dw:1433036725634:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1inequality dw:1433036745339:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1the inequality includes the shaded region which extends forever downward and to the right (below the line y = x1)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay i see the difference between an inequality and equation, for an inequality you must shade or make dashed depending on if its equal to or not but for an equation you just draw the line.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1correct, I forgot about that part

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1since y < x1 has no line under the < sign, we need a dashed boundary line

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1but you can easily make it \[\Large y \le x1\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay so let me show you my answer for part A: Its the same as i showed above just with the inequalities underneath it because i don't know what more to explain.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This is for an online course so i can't draw graphs or anything i just type explanations :/

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1then do your best to describe the equations/graphs. So mention the points involved and the direction of the shading, and the boundary line type

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1dw:1433036996621:dw this boundary line goes through (3,2) and (4,3) it is a dashed boundary line (assuming you go with y < x1) the shading is below the boundary line

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay let me explain it here then ill transcribe it. Part A: Continuation  After graphing y<x1 i should shade below this line, i can figure this out by testing points above or below the line, i've figured out that points above the line don't work but those underneath do, so this is why i've shaded below y<x1, same for the line y>x2, i shaded above it because when i test points below it does not work, now i can shade infinitley if i wanted too, but i am only shading where both shades meet from y>x2 and y<x1 to receive the system of inequalities...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If i add that on to my first answer does it make it complete?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1yes that wraps up part A

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay now could you help me answer parts B and C???

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1Part B: Explain how to verify that the points A and E are solutions to the system of inequalities created in Part A.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1I'll show you how to verify point A and I'll let you verify point E

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1verifying point A point A is (x,y) = (2,3) y < x1 3 < 21 ... plug in (x,y) = (2,3) 3 < 1 ... this is true  y > x  2 3 > 2  2 ... plug in (x,y) = (2,3) 3 > 4 ... this is true  since y < x1 AND y > x  2 are true at the same time for the ordered pair (2,3), this confirms that point A is indeed in the solution set of this system of inequalities

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh i see so you just tested point A for both inequalities and it proved true.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Now i would have to do the same for E

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay do i have to show this work or can i just explain it for part B?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1showing work is always a good idea, but I guess you could explain it if you want. It will depend on how the teacher wants it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay ill just show your work for A then explain for E.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay now on to the final part C

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1Part C: William can only attend a school in his designated zone. William's zone is defined by y < x  1. Explain how you can identify the schools that William is allowed to attend.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1so the goal here is to figure out which points (A through F) satisfy y < x1

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1and you can use steps similar to what I had done in part B

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Btw pOINTS a THROUGH f ARE SCHOOLS in a city

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So do i just test all points in y>1x to solve for c??

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1you mean y < x1, right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh okay so my Answer for Part C would look like Part C: William can only attend schools that satisfy his zone which is y<x1, to figure out which schools would satisfy this i must plug in points A through F into this inequality and see which are true, those that are true are schools that William can attend those that are false or don't make sense are those that he can not attend.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1so which points make y < x1 true?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1you provided the explanation as to how to find the points, but I think they also want the points listed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It doesn't say that.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It says "Explain how you can Identify the schools that william is allowed to attend" Not list the schools

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So does that mean my answer is correct???

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1yeah if they don't want the list, then you have it completed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay i have one more question could you help me on it??

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1what's the question?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh, its like a whole other problem with parts a,b,c

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Could you give me about 10 minutes or so, i just wanna transcribe the work on here to my worksheet.
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