anonymous
  • anonymous
I need help in finding the range of the following function: arcsin(3x+1) For finding the domain I did the following... -1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Vocaloid
  • Vocaloid
yup, looks good to me! great job ~
anonymous
  • anonymous
Great! Thanks @Vocaloid :) Ant ideas on how to find the range?
anonymous
  • anonymous
Any*

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Vocaloid
  • Vocaloid
Hm, that's a bit trickier, I suppose you could evaluate arcsin(-2/3) and arcsin(0), but I'm sure there's a better way, let me think about this one for a second
anonymous
  • anonymous
Alrighty! :D Thanks so much!
anonymous
  • anonymous
I think the range of arcsin x is always -π/2 ≤ y ≤ π/2
anonymous
  • anonymous
Wait would it be pi/2 - 3pi/2 ?
jim_thompson5910
  • jim_thompson5910
I think you meant to say this for the domain \[\Large -1 \le 3x{\color{red}+}1 \le 1\] and you solve for x from there
Vocaloid
  • Vocaloid
yes, peachpi is right, silly me!
anonymous
  • anonymous
@jim_thompson5910 you caught my typo again >.<
anonymous
  • anonymous
@peachpi thank you!
jim_thompson5910
  • jim_thompson5910
but you have the correct result after you isolate x \[\Large -\frac{2}{3} \le x \le 0\] is the correct domain
anonymous
  • anonymous
you're welcome
anonymous
  • anonymous
@jim_thompson5910 okay so would be correct to find the range by just plugging in -2/3 and 0 ?
anonymous
  • anonymous
*would it
jim_thompson5910
  • jim_thompson5910
yep, plugging in x = -2/3 will give -pi/2 which is the lowest you can go in the range plugging in x = 0 will give pi/2 which is the highest you can go in the range

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