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anonymous
 one year ago
Find the distance between the point (5,6), and the line 2x3y+2=0
a) 6
b) radical 13
c) 6 radical 13/ 13
d)5 radical 2
anonymous
 one year ago
Find the distance between the point (5,6), and the line 2x3y+2=0 a) 6 b) radical 13 c) 6 radical 13/ 13 d)5 radical 2

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pooja195
 one year ago
Best ResponseYou've already chosen the best response.0@Loser66 ? do u know ;; ?

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2distance formula for point and line: given the point (x,y) and line in the form Ax + By = C the distance is given by: d = Ax + By + C / sqrt(A^2 + B^2)

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2dw:1433039250805:dw just to make it a little more clear

Vocaloid
 one year ago
Best ResponseYou've already chosen the best response.2ACTUALLY, WAIT, just a small correction! the line should be in the form Ax + By + C = 0 but everything else is correct

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1dw:1433039388871:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1dw:1433039400397:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1Find the equation of the line that is perpendicular to 2x3y+2=0 and this perpendicular line goes through this point dw:1433039456627:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1mark the point of intersection between these two lines as point P dw:1433039484436:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1dw:1433039495540:dw the answer you want is the distance d (use the distance formula to compute that distance)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you guys so much I'm I think I'm going something wrong with the calculation Idk what is it

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1what are you getting for the equation of the perpendicular line?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.113 is a number, not an equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1433039896275:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I give up I've no idea how to do it

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.12x3y+2=0 2x3y+22=02 2x3y = 2

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1swap the coefficients on 2x3y = 2 to get 3x+2y = 2 then make the x coefficient positive to get 3x+2y = 2 3x+2y = 2 is perpendicular to 2x3y = 2, but we don't know if the perpendicular line goes through (5,6)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1Any equation perpendicular to the given line is of this form 3x+2y = C where C is any real number plug in (x,y) = (5,6) 3x+2y = C 3(5)+2(6) = C 27 = C C = 27 so the equation 3x+2y = 27 is perpendicular to the given equation AND it goes through (5,6) dw:1433040359530:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1now solve this system of equations 2x3y = 2 3x+2y = 27 to find the intersection point P dw:1433040425688:dw
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