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anonymous

  • one year ago

Find the distance between the point (5,6), and the line 2x-3y+2=0 a) 6 b) radical 13 c) 6 radical 13/ 13 d)5 radical 2

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  1. pooja195
    • one year ago
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    @Loser66 ? do u know ;-; ?

  2. Vocaloid
    • one year ago
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    distance formula for point and line: given the point (x,y) and line in the form Ax + By = C the distance is given by: d = |Ax + By + C| / sqrt(A^2 + B^2)

  3. Vocaloid
    • one year ago
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    |dw:1433039250805:dw| just to make it a little more clear

  4. Vocaloid
    • one year ago
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    ACTUALLY, WAIT, just a small correction! the line should be in the form Ax + By + C = 0 but everything else is correct

  5. jim_thompson5910
    • one year ago
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    |dw:1433039388871:dw|

  6. jim_thompson5910
    • one year ago
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    |dw:1433039400397:dw|

  7. jim_thompson5910
    • one year ago
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    Find the equation of the line that is perpendicular to 2x-3y+2=0 and this perpendicular line goes through this point |dw:1433039456627:dw|

  8. jim_thompson5910
    • one year ago
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    mark the point of intersection between these two lines as point P |dw:1433039484436:dw|

  9. jim_thompson5910
    • one year ago
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    |dw:1433039495540:dw| the answer you want is the distance d (use the distance formula to compute that distance)

  10. anonymous
    • one year ago
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    Thank you guys so much I'm I think I'm going something wrong with the calculation Idk what is it

  11. jim_thompson5910
    • one year ago
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    what are you getting for the equation of the perpendicular line?

  12. anonymous
    • one year ago
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    13

  13. jim_thompson5910
    • one year ago
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    13 is a number, not an equation

  14. anonymous
    • one year ago
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    |dw:1433039896275:dw|

  15. anonymous
    • one year ago
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    I'm not even sure

  16. anonymous
    • one year ago
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    I give up I've no idea how to do it

  17. jim_thompson5910
    • one year ago
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    2x-3y+2=0 2x-3y+2-2=0-2 2x-3y = -2

  18. jim_thompson5910
    • one year ago
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    swap the coefficients on 2x-3y = -2 to get -3x+2y = -2 then make the x coefficient positive to get 3x+2y = -2 3x+2y = -2 is perpendicular to 2x-3y = -2, but we don't know if the perpendicular line goes through (5,6)

  19. jim_thompson5910
    • one year ago
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    Any equation perpendicular to the given line is of this form 3x+2y = C where C is any real number plug in (x,y) = (5,6) 3x+2y = C 3(5)+2(6) = C 27 = C C = 27 so the equation 3x+2y = 27 is perpendicular to the given equation AND it goes through (5,6) |dw:1433040359530:dw|

  20. jim_thompson5910
    • one year ago
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    now solve this system of equations 2x-3y = -2 3x+2y = 27 to find the intersection point P |dw:1433040425688:dw|

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