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anonymous
 one year ago
COuld someone please help! im tired and i want to go to bed! ill give medals and whatever you need!
A function is shown below:
f(x) = x3 + 3x^2  x  3
Part A: What are the factors of f(x)? Show your work.
Part B: What are the zeros of f(x)? Show your work.
Part C: What are the steps you would follow to graph f(x)? Describe the end behavior of the graph of f(x).
anonymous
 one year ago
COuld someone please help! im tired and i want to go to bed! ill give medals and whatever you need! A function is shown below: f(x) = x3 + 3x^2  x  3 Part A: What are the factors of f(x)? Show your work. Part B: What are the zeros of f(x)? Show your work. Part C: What are the steps you would follow to graph f(x)? Describe the end behavior of the graph of f(x).

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@dan815 @nincompoop please help im really sorry for bothering you but i need help

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i am so sorry for tagging everyone but i really need help

dan815
 one year ago
Best ResponseYou've already chosen the best response.11 is a root because if u plug in 1 it goes to 0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it could be a factor of f(x)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i am so sorry if i come off as really stupid i am pretty much fried from all the work iv been doing

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im so sorry for bothering you my brother just actually came home and helped me do it. i am really sorry for being a nuisance

dan815
 one year ago
Best ResponseYou've already chosen the best response.1a root means that there is a point when x= that root y=0

dan815
 one year ago
Best ResponseYou've already chosen the best response.1that means this polynomail must have a (xr) (ax^2+bx+c) if r is the root term

dan815
 one year ago
Best ResponseYou've already chosen the best response.1now we say that 1 is a root so, (x+1) is a factor of x3 + 3x^2  x  3 to see what the (ax^2+bx+c) part what we do is x3 + 3x^2  x  3  = use syntetic division and see what this is (x+1) this must be the ax^2+bx+c part except you would have solved for a b and c part Then you can see if you can continue to factor this (ax^2+bx+c) and make (xr) (ax^2+bx+c) = (xr1) (xr2)(xr3) into this completely product ant root form, r1,r2,r3 are the roots in this case r1=1 (x(1))(xr2)(xr3) = (x+1)(xr2)(xr3) you still have to find r2 and r3 not that isnt a square or cube on r2 and r3 that is an index.
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