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anonymous

  • one year ago

COuld someone please help! im tired and i want to go to bed! ill give medals and whatever you need! A function is shown below: f(x) = x3 + 3x^2 - x - 3 Part A: What are the factors of f(x)? Show your work. Part B: What are the zeros of f(x)? Show your work. Part C: What are the steps you would follow to graph f(x)? Describe the end behavior of the graph of f(x).

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  1. anonymous
    • one year ago
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    @dan815 @nincompoop please help im really sorry for bothering you but i need help

  2. anonymous
    • one year ago
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    @saifoo.khan

  3. anonymous
    • one year ago
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    @sammixboo

  4. anonymous
    • one year ago
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    @Australopithecus

  5. anonymous
    • one year ago
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    i am so sorry for tagging everyone but i really need help

  6. anonymous
    • one year ago
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    @paki

  7. dan815
    • one year ago
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    -1 is a root because if u plug in -1 it goes to 0

  8. anonymous
    • one year ago
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    so it could be a factor of f(x)

  9. anonymous
    • one year ago
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    i am so sorry if i come off as really stupid i am pretty much fried from all the work iv been doing

  10. anonymous
    • one year ago
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    @dan815

  11. anonymous
    • one year ago
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    im so sorry for bothering you my brother just actually came home and helped me do it. i am really sorry for being a nuisance

  12. dan815
    • one year ago
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    okay soq

  13. dan815
    • one year ago
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    listen

  14. dan815
    • one year ago
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    a root means that there is a point when x= that root y=0

  15. dan815
    • one year ago
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    that means this polynomail must have a (x-r) (ax^2+bx+c) if r is the root term

  16. dan815
    • one year ago
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    now we say that -1 is a root so, (x+1) is a factor of x3 + 3x^2 - x - 3 to see what the (ax^2+bx+c) part what we do is x3 + 3x^2 - x - 3 ----------------- = use syntetic division and see what this is (x+1) this must be the ax^2+bx+c part except you would have solved for a b and c part Then you can see if you can continue to factor this (ax^2+bx+c) and make (x-r) (ax^2+bx+c) = (x-r1) (x-r2)(x-r3) into this completely product ant root form, r1,r2,r3 are the roots in this case r1=-1 (x-(-1))(x-r2)(x-r3) = (x+1)(x-r2)(x-r3) you still have to find r2 and r3 not that isnt a square or cube on r2 and r3 that is an index.

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