A sample of 168 individuals is selected, and the individuals are classified according to their smoking habits and the smoking habits of their parents. The results are given in the contigency table below. What is the relative frequency of individuals in the sample who have two parents who do not smoke?

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A sample of 168 individuals is selected, and the individuals are classified according to their smoking habits and the smoking habits of their parents. The results are given in the contigency table below. What is the relative frequency of individuals in the sample who have two parents who do not smoke?

Mathematics
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First you need to find the totals of the values in the 2 rows and the 3 columns of the contingency table. Then you divide the total number of individuals who have parents neither of which smoke by 168.
well I did 168 divided by 18 and got 9.33333 because that is the only family who doesnt smoke

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I mean 47 my bad hold on
I got 3.57
ok sratch that I got 2.5 because I added 47 and 23
When I added the number of individuals who smoke, but have both parents non-smokers (23 individuals) to the number of individuals who don't smoke and who have both parents non-smokers (47 individuals) I get the following: 23 + 47 = 70 The relative frequency of individuals in the sample who have two parents who do not smoke is then given by: \[\large \frac{70}{168}= this\ fraction\ needs\ simplifying\]
yeah and I got 5/12
Correct!
wait! @kropot72 there is no option to simply, I need to round my answers to a decimal.
all you need to do is put 5/12 into a calculator, and it'll give you 5/12 in decimal form
What he said. ^^^^^
@atlantaslast How many decimal places are required in the answer?
two decimals places.
Then you will need to round up in this case.
how would that be? I just guessed and put 4.1 because it said 0.4166666
but it might be 1.6
Not really. ).416666666 rounded to two decimal places is 0.42.
so the answer would be 0.42?
Correct.
Thanks :)
you're welcome :)

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