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anonymous
 one year ago
sin theta= 3/5
cos beta = 2sqrt6/5
Find sin(theta+beta). Is the answer 6sqrt6+4/25?
anonymous
 one year ago
sin theta= 3/5 cos beta = 2sqrt6/5 Find sin(theta+beta). Is the answer 6sqrt6+4/25?

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shamim
 one year ago
Best ResponseYou've already chosen the best response.0R u able to find out Cos theta=?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[\sin (\theta) = \frac{3}{5}, \cos(\beta) = 2\sqrt{\frac{6}{5}}\] ? I'm confused on what cosine beta should be

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2oh yeah we need sin beta and cosine beta otherwise the angle sum identity formula isn't going to work

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[\sin(\theta + \beta) = \sin(\theta)\cos(\beta)+\cos(\theta)\sin(\beta)\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2so far we have sin (theta) = 3/5 dw:1433043667731:dw so cos (theta) = 4/5

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2ummm what was the cosine beta?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2is it \[\cos(\beta) = 2 \frac{\sqrt{6}}{5} ?\] is the square root inside the 6/5? that part is throwing me off

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[\sin(\theta + \beta) = \frac{3}{5}\cos(\beta)+\frac{4}{5}\sin(\beta)\] I don't understand what cosine beta is... but I do know that I need another triangle so I can grab sin beta and we add this all together

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2is the 6/5 fraction inside the whole square root or is it just square root 6 / 5 ?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[\cos(\beta) = 2 \frac{\sqrt{6}}{5} ? \] or \[\cos(\beta) = 2 \sqrt{\frac{6}{5}} \]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2I need clarification on that part... otherwise I might end up with the wrong answer.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2dw:1433044545197:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[\sin(\theta + \beta) = \frac{3}{5}\frac{2\sqrt{6}}{5}+\frac{4}{5} (\frac{1}{5})\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{6\sqrt{6}}{25}+\frac{4}{25}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2I relooked at cos beta and realized that 5 was the longest side of the triangle and that 2 sqrt{6} was the adjcent part... needed to find the opposite part of the triangle so I could find sin beta.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.2you got the right answer.
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